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2 years ago

H2 Worksheet #8

Mathematics

1 answer:

ohaa [14]2 years ago

3 0

Answer:

It's easy to solve the problem.

let's start...

given equation:- y = 2x+2

X y

1 (2× 1 )+ 2 = 4 .

3 (3×2)+2 = 8 .

9 (9×2) + 2 = 20 .

10. (10× 2)+2 = 22 .( table completed)

just put the value of X in the expression.

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Sin tita= 0.6892.find the value Of tita correct to two decimal places<br><br>

Anvisha [2.4K]

Answer:

$\theta \approx 6.28n + 2.38, \quad n \in \mathbb{Z}$

$\theta \approx 6.28n + 0.76, \quad n \in \mathbb{Z}$

Considering $\theta \in (0, 2\pi]$

$\theta \approx 2.38$

$\theta \approx 0.76$

Step-by-step explanation:

$\sin(\theta)=0.6892$

We have:

$\sin (x)=a \Longrightarrow x=\arcsin (a)+2\pi n \text{ or } x=\pi -\arcsin (a)+2\pi n \text{ as } n\in \mathbb{Z}$

Therefore,

$\theta= \arcsin (0.6892)+2\pi n, \quad n \in \mathbb{Z}$

$\theta = \pi -\arcsin (0.6892)+2\pi n, \quad n\in \mathbb{Z}$

---------------------------------

$\theta \approx 6.28n + 2.38, \quad n \in \mathbb{Z}$

$\theta \approx 6.28n + 0.76, \quad n \in \mathbb{Z}$

4 0

3 years ago

Use the diagram to answer the question

koban [17]

Answer:

$m\angle EFG=52^{o}$

Step-by-step explanation:

We have been given that line m is parallel to line p, $m\angle HEF=39^{o}$ and $m\angle IGF=13^{o}$ .

Since line m is parallel to line p and EJ is a transversal, so measure of angle EJG will be 39 degrees as angle EJG is alternate interior angle of angle HEF. Both angles are inside parallel lines m and p and on opposite side of transversal EJ.

We can see that angle EFG is exterior angle of triangle GFJ. Since the measure of an exterior angle of a triangle equals to the sum of the opposite interior angles.

We can see that angle IGF and angle EJG are opposite interior angles of angle EFG.

$m\angle EFG=m\angle IGF+m\angle EJG$