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tatyana61 [14]
2 years ago
7

The following scatterplot shows the percentage of the vote a candidate received in the 2016 senatorial elections

Mathematics
1 answer:
alex41 [277]2 years ago
6 0

The critical values corresponding to a 0.01 significance level used to test the null hypothesis of ρs = 0 is (a) -0.881 and 0.881

<h3>How to determine the critical values corresponding to a 0.01 significance level?</h3>

The scatter plot of the election is added as an attachment

From the scatter plot, we have the following highlights

  • Number of paired observations, n = 8
  • Significance level = 0.01

Start by calculating the degrees of freedom (df) using

df =n - 2

Substitute the known values in the above equation

df = 8 - 2

Evaluate the difference

df = 6

Using the critical value table;

At a degree of freedom of 6 and significance level of 0.01, the critical value is

z = 0.834

From the list of given options, 0.834 is between  -0.881 and 0.881

Hence, the critical values corresponding to a 0.01 significance level used to test the null hypothesis of ρs = 0 is (a) -0.881 and 0.881

Read more about null hypothesis at

brainly.com/question/14016208

#SPJ1

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see explanation

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7 0
3 years ago
The fish population in a pond with carrying capacity 1200 is modeled by the following logistic equation where N(t) denotes the n
MArishka [77]

9514 1404 393

Answer:

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  142 fish

Step-by-step explanation:

A) The differential equation is modified by adding a -50 fish per year constant term:

  (dN)/(dt) = (0.4)/(1200)N(1200-N) -50

__

B) The steady-state value of the fish population will be when N reaches the value that makes dN/dt = 0.

  (0.4/1200)(N)(1200-N) -50 = 0

  N(N-1200) = -(50)(1200)/0.4) . . . . rewrite so N^2 has a positive coefficient

  N^2 -1200N + 600^2 = -150,000 +600^2 . . . . complete the square

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  N = 600 + √210,000 ≈ 1058

This steady-state number of fish is ...

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8 0
3 years ago
The spring of a spring balance is 5.0in. long when there is no weight on the balance, and it is 8.4in. long with 4.0 lb hung fro
djyliett [7]

Answer: work is done in stretching it from 5.0in. to a length of 12.8in is 36 lb.In

Step-by-step explanation:

We know that

f(x) = kx

given that;

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x = 8.4 - 5 = 3.4

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we substitute

4 = k × 3.4

k = 4 / 3.4

k = 1.1764 = 20/17

Now work done from natural length to 12.8

x = 12.8 - 5 = 7.8

work done = ₀∫^7.8  f(x) dx

= ₀∫^7.8  kx dx

we substitute value of k

= ₀∫^7.8  (20/17)x dx

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= 1.1764 × 30.42

= 35.786 ≈ 36 lb.In

Therefore work is done in stretching it from 5.0in. to a length of 12.8in is 36 lb.In

4 0
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