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Evgesh-ka [11]
3 years ago
7

Find the distance between the set of points (3, -3) and (3, 7)

Mathematics
1 answer:
Jobisdone [24]3 years ago
4 0

Answer: 10

Step-by-step explanation:

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Let t be time in seconds and let r(t) be the rate, in gallons per second, that water enters a reservoir: r(t)=700−40t. a) For 0≤
Flura [38]
What you don't want is the value of r(t) becoming negative. Surely that would represent water escaping the reservoir.

How big can (t) get before water actually starts escaping the reservoir?

Essentially, to figure this out r(t) would have to be equal to 0. 

700 - 40t = 0

40t=700

t=700/40=17.5

So the first answer is 17.5 seconds. After this amount of time has elapsed the reservoir will start to lose water as r(t) would become negative.

---------------

The reservoir had the least amount of water in it before it was being filled. That was when t=0. The volume of water in the reservoir wasn't negatively impacted as not enough water had escaped it during the 17.5 to 30 second period.
7 0
3 years ago
Answer all please? tysm
8_murik_8 [283]
1.A 2.D 3.B These are the answers I think is the choice to your question.
6 0
3 years ago
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Find the definding set of the function: y= √(1 - Cos3x ) / (1 + Sin4x )
ryzh [129]

y = \frac{\sqrt{\left( 1 - \cos (x\,\text{Rationalize}(0.0523599))\right) }}{\sqrt{\left( 1+\sin (x\,\text{Rationalize}(0.0698132))\right) }}

6 0
3 years ago
Jay organised a large wedding and 1/3 of them chose beef 5/12 of them chose Chicken and 69 of them chose vegetarian so how many
DerKrebs [107]

Answer:

276 Guests

Step-by-step explanation:

Calculation to determine how many guest were at the wedding

Guests that choose beef =1/3

Guests that choose chicken= 5/12

Guests that choose vegetarian=69

Now let calculate the how many guest were at the wedding

Let x represent the numbers of guest that were present at the wedding

Hence,

x/3 + 5x/12 + 69 = x

9x/12 + 69 = x

12x/12 - 9x/12 = 69

3x/12 = 69

x/4 = 69

x=69*4

x = 276 guests

Therefore the numbers of guests that were at the wedding is 276

7 0
3 years ago
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HELP ME PLEASE HELP ME!
alexgriva [62]
The chance of picking a almond cookie the first time:
you have 6 cookies, 3 of them are almond
So the chance of taking an almond cookie is
\frac{3}{6}  =  \frac{1}{2}
The second time there are 5 cookies left, 2 of them are almond cookies
The chance of taking an almond cookie is
\frac{2}{5}
To know the probability of picking two almond cookies in a row, multiply the changes:
\frac{1}{2}  \times  \frac{2}{5}  =  \frac{1}{5}
The chance of taking two almond cookies is 1/5
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3 years ago
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