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2 years ago

What is the sum of 4.2 × 105 and 5.3 × 105?

2 answers:

4 0

The answer would be 9.5•105. You are supposed to add the beginning numbers since the second numbers are equal to each other meaning that the first numbers are of the base values.

marishachu [46]2 years ago

3 0

Answer: $9.5\times 10^5$

Step-by-step explanation:

The given exponents : $4.2\times10^5$ and $5.3\times10^5$

When we add them together , we get

$4.2\times10^5+5.3\times 10^5 \\\\=(4.2+5.3)\times10^5\ \ \text{[By using distributive property } ba+ca=(b+c)a]\\\\= 9.5\times10^5$

Hence, the sum of $4.2\times10^5$ and $5.3\times10^5=9.5\times 10^5$

You might be interested in

What are the coordinates of each point after quadrilateral ABCD is reflected across the y-axis and then translated 2 units down?

zheka24 [161]

Answer:

$A" =(-1,-1)$ $B" =(-2,1)$

$C" =(-4,1)$ $D" =(-5,-1)$

Step-by-step explanation:

Given

$A = (1,1)$ $B =(2,3)$

$C = (4,3)$ $D = (5,1)$

Required

The new coordinates after reflected across y-axis and shifted 2 units down

When a point is reflected across the y-axis, the rule is:

$(x,y)=>(-x,y)$

So:

$A = (1,1)$ $=> A' = (-1,1)$

$B =(2,3)$ $=> B' = (-2,3)$

$C = (4,3)$ $=> C' = (-4,3)$

$D = (5,1)$ $=> D' = (-5,1)$

When a point is translated 2 units down, the rule is:

$(x,y) => (x,y-2)$

So:

$A = (1,1)$ $=> A' = (-1,1)$ $=> A" =(-1,-1)$

$B =(2,3)$ $=> B' = (-2,3)$ $=> B" =(-2,1)$

$C = (4,3)$ $=> C' = (-4,3)$ $=> C" =(-4,1)$

$D = (5,1)$ $=> D' = (-5,1)$ $=> D" =(-5,-1)$

So, the new coordinates are:

$A" =(-1,-1)$ $B" =(-2,1)$

$C" =(-4,1)$ $D" =(-5,-1)$

5 0

2 years ago

What is the slope of y = 4 -2x?

erastovalidia [21]

Answer:

Step-by-step explanation:

The slope-intercept form of an equation of a line:

$y=mx+b$

m - slope

b - y-intercept

We have

$y=4-2x=-2x+4$

Therefore the slope is equal to -2.

8 0

2 years ago

HELP

larisa86 [58]

It looks like the parabola are going down, so the coefficient should be negative,
B or C,
then we see that the parabola has x -intercepts (1,0) and (5,0)
these roots should be written as multiples
x=1, so x-1=0
and
x=5, so x-5=0,
so (x-1)(x-5) and negative first coefficient -2 at the same time.
We can see only in the
B. <span>f(x) = –2(x – 5)(x – 1)</span>

7 0

2 years ago

Read 2 more answers

Circle O, with center (x, y) passes through the points A(0, 0), B(-3, 0), and C(1, 2). Find the coordinates of the center of the

KonstantinChe [14]

Answer:

The center of the circle is

$(-\frac{3}{2},2)$

Step-by-step explanation:

Let the equation of the circle be

$x^2+y^2+2ax+2by+c=0$ , where (-a,-b) is the center of this circle.

The points lying the circle must satisfy the equation of this circle.

A(0,0)

We substitute this point to get;

$0^2+0^2+2a(0)+2b(0)+c=0$

$\implies c=0$

B(-3,0)

$(-3)^2+0^2+2a(-3)+2b(0)+c=0$

$\implies 9+0-6a+0+c=0$

$\implies -6a+c=-9$

But c=0

$\implies -6a=-9$

$\implies a=\frac{3}{2}$

C(1,2)

$1^2+2^2+2a(1)+2b(2)+c=0$

$1+4+2a+4b+c=0$

$2a+4b+c=-5$

Put the value of 'a' and 'c' to find 'b'

$2(\frac{3}{2})+4b+0=-5$

$3+4b+0=-5$

$4b=-5-3$

$4b=-8$

b=-2

Hence the center of the circle is

$(-\frac{3}{2},2)$

8 0

3 years ago

What is the slope of a line that is perpendicular to the line y=-1/3x-6?

max2010maxim [7]

Y=-1/3x-6, for this line, the slope (m) is -1/3.
This is because the equation is in the slope intercept form: y = mx + b.
The perpendicular line to one with m = -1/3, is the negative reciprocal of m, we'll call it m2.
m2 = --3/1 = +3/1 = 3

4 0

2 years ago