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1 year ago

Solve the following equation -3x+5<20

Mathematics

1 answer:

skelet666 [1.2K]1 year ago

6 0

The solution of the inequality is x > -5

<h3>How to solve inequality?</h3>

In equality are expression that contains <, >, ≤ and ≥.

Inequality are operator use for comparison.

Therefore,

-3x + 5 < 20

subtract 5 from both sides of the inequality

-3x + 5 < 20

-3x + 5 - 5 < 20 - 5

-3x < 15

divide both sides by -3

-3x < 15

-3x / -3 < 15 / -3

x > - 5

Therefore, x > -5

Learn more about inequality here: brainly.com/question/11482456

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3 years ago

ABCD is a parallelogram. Segment AC = 4x + 10. Find the value of x and y.

valkas [14]

Answer:

The values of x and y in the diagonals of the parallelogram are x=0 and y=5

Step-by-step explanation:

Given that ABCD is a parallelogram

And segment AC=4x+10

From the figure we have the diagonals AC=3x+y and BD=2x+y

By the property of parallelogram the diagonals are congruent

∴ we can equate the diagonals AC=BD

That is 3x+y=2x+y

3x+y-(2x+y)=2x+y-(2x+y)

3x+y-2x-y=2x+y-2x-y

x+0=0 ( by adding the like terms )

∴ x=0

Given that segment AC=4x+10

Substitute x=0 we have AC=4(0)+10

=0+10

=10

∴ AC=10

Now (3x+y)+(2x+y)=10

5x+2y=10

Substitute x=0, 5(0)+2y=10

2y=10

$y=\frac{10}{2}$

∴ y=5

∴ the values of x and y are x=0 and y=5

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3 years ago