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3 years ago

Micheal is three time as old as Jean in seven year he will be twice old as she will be then how old are they both

Mathematics

1 answer:

PtichkaEL [24]3 years ago

5 0

Answer:

Michael is 21 years old while Jean is 7 years old.

Step-by-step explanation:

Given that Micheal is three times as old as Jean, but in seven years he will be twice old as she will be, to determine how old are they both at this time, the following calculation must be performed:

M = 3J

M + 7 = 2J + 7

7 = 1/3

7 x 3 = 21

21 + 7 = 28

7 + 7 = 14

21 / 7 = 3

28 / 14 = 2

Therefore, Michael is 21 years old while Jean is 7 years old.

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3 years ago

Solve and check the following equation. 8d + 21 = 12d + 5 d =

olganol [36]

Subtract 8d from both sides

21 = 12d + 5 - 8d

Simplify 12d + 5 - 8d to 4d + 5

21 = 4d + 5

Subtract 5 from both sides

21 - 5 = 4d

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Divide both side by 4

16/4 = d

Simplify 16/4 to 4

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3 0

3 years ago

The probability of drawing a heart from a standard deck of cards is 0.25. You record the car do you draw and return the car befo

Licemer1 [7]

Answer: C) 0.112

Step-by-step explanation:

In binomial distribution with parameters n (Total trails) and p (probability of getting success sin each trial) , the probability of getting success in x trials is given by :-

$P(X=x)=^nC_xp^x(1-p)^{n-x}$

Given : The probability of drawing a heart from a standard deck of cards is 0.25

Here , getting heart is the success.

Then p= 0.25

For n= 20

The probability that you will draw a heart seven times i.e. x= 7:

$P(X=7)=^{20}C_7(0.25)^7(1-0.25)^{20-7}$

$P(X=7)=\dfrac{20!}{7!(20-7)!}(0.25)^7(1-0.25)^{20-7}\ \ [\because\ ^nC_r=\dfrac{n!}{r!(n-r)!}]$

$=\dfrac{20\times19\times18\times17\times16\times15\times14\times13!}{7!13!}(0.25)^7(0.75)^{13}\\\\=77520(0.00006103515625)(0.0237572640181)\\\\=0.112406195476\approx0.112$

Hence, the probability that you will draw a heart seven times = 0.112

Thus , the correct answer is C) 0.112 .

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3 years ago

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Mariulka [41]

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