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statuscvo [17]
1 year ago
12

Find an equation of the line perpendicular to y = - 2x + 2

Mathematics
1 answer:
kondaur [170]1 year ago
7 0

Answer:

<u><em>y = (1/2)x + 1</em></u>

Step-by-step explanation:

y=mx+b, where m is the slope and b the y-intercept (the value of y when x = 0).  We are given y = -2x + 2 as the reference line and are asked to find a line that is perpendicular to it.  (We'll get to the (2,2) thing later).

A perpendicular line has a slope that is the negative inverse of the reference line slope, which in this case is -2 (the m).  The negative inverse of -2 is -(-1/2) or (1/2),  This measn the perpendicular line will have the form:

     y = (1/2)x + b

The complication is that we want this new line to go through point (2,2).  Easy.  Just substitute (2,2) in the aboove ea=quation and solve for b:

y = (1/2)x + b  for (2,2)

<u>2</u> = (1/2)<u>2</u> + b

b = 2 - 1, b = 1

The equation of the line perpendicular to y = -2x + 2 is <u>y = (1/2)x + 1,</u>

<u></u>

See attached graph for proof.

                       

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Answer:

the probability of no defects in 10 feet of steel = 0.1353

Step-by-step explanation:

GIven that:

A roll of steel is manufactured on a processing line. The anticipated number of defects in a 10-foot segment of this roll is two.

Let consider β to be the average value for defecting

So;

β = 2

Assuming Y to be the random variable which signifies the anticipated number of defects in a 10-foot segment of this roll.

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the probability mass function can be represented as follows:

\mathtt{P(y) = \dfrac{e^{- \beta} \ \beta^ \ y}{y!}}

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y = 0

\mathtt{P(y =0) = \dfrac{e^{- 2} \ 2^ \ 0}{0!}}

\mathtt{P(y =0) = \dfrac{0.1353  \times 1}{1}}

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