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3 years ago

WHO acancer 100 multiplications by fours and fives

Mathematics

2 answers:

Charra [1.4K]3 years ago

8 0

1x5=5
2×5 = 10
3×5 = 15
4×5 = 20
5×5 = 25
5×6 = 30
5×7 = 35
5×8 = 40
5×9 = 45
5×10 = 50
5×11 = 55
5×12 = 60

attashe74 [19]3 years ago

5 0

The answer will be 4x25

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Circumference of a circle = 3.14 * 26 feet

Circumference of a circle = 81.64 feet

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Answer:

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Step-by-step explanation:

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2 years ago

What is the number? 10% more than a number is 132.

Elena-2011 [213]

Step-by-step explanation:

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3 years ago

John had $500 Anna has $400 Peter had $700 Who has the most?

vladimir2022 [97]

Answer:

Peter has the most

Step-by-step explanation:

Peter has the most amount of the money of the three of them.

From the question, we see that John had only $500 while Anna has $400 and Peter had $700. Which means, of all the three of them; John, Anna and Peter, Peter had the most because he had $700 the greatest amount of the three of them, which is followed by John who had $500, the greater and Anna had the least of it, $400.

Arranging from the Person who had the most of money, we have Peter with $700, John with $500 and lastly, Anna with $400.

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3 years ago

Read 2 more answers

Find the general solution to 1/x dy/dx - 2y/x^2 = x cos x, y(pi) = pi^2

Finger [1]

Answer:

$\frac{y}{x^2}=\sin x+\pi$

Step-by-step explanation:

Consider linear differential equation $\frac{\mathrm{d} y}{\mathrm{d} x}+yp(x)=q(x)$

It's solution is of form $y\,I.F=\int I.F\,q(x)\,dx$ where I.F is integrating factor given by $I.F=e^{\int p(x)\,dx}$ .

Given: $\frac{1}{x}\frac{\mathrm{d} y}{\mathrm{d} x}-\frac{2y}{x^2}=x\cos x$

We can write this equation as $\frac{\mathrm{d} y}{\mathrm{d} x}-\frac{2y}{x}=x^2\cos x$

On comparing this equation with $\frac{\mathrm{d} y}{\mathrm{d} x}+yp(x)=q(x)$ , we get $p(x)=\frac{-2}{x}\,\,,\,\,q(x)=x^2\cos x$

I.F = $e^{\int p(x)\,dx}=e^{\int \frac{-2}{x}\,dx}=e^{-2\ln x}=e^{\ln x^{-2}}=\frac{1}{x^2}$ { formula used: $\ln a^b=b\ln a$ }

we get solution as follows:

$\frac{y}{x^2}=\int \frac{1}{x^2}x^2\cos x\,dx\\\frac{y}{x^2}=\int \cos x\,dx\\\\\frac{y}{x^2}=\sin x+C$

{ formula used: $\int \cos x\,dx=\sin x$ }

Applying condition: $y(\pi)=\pi^2$

$\frac{y}{x^2}=\sin x+C\\\frac{\pi^2}{\pi}=\sin\pi+C\\\pi=C$

So, we get solution as :

$\frac{y}{x^2}=\sin x+\pi$

4 0

3 years ago