Answer:
5.579 * or 0.00005579 %
Step-by-step explanation:
In this question, you select 11 random adults, so the order is not important and we should use combination instead of permutation. There are two different probability here
A= chance that the adults need correction= 0.81
B= chance that the adult doesn't need correction = 0.19
The case that can fulfill the condition of no more than 1 of 11 adults need correction is:
1. 0 adult need correction = 0C11 *
2. 1 adult need correction = 1C11 * *
Then the probability will be:
0C11 * +1C11 * * =
* + * *0.81 =
5.579 * = 0.00005579 %
The threshold for a significant value that widely used is 5% and the chance is lower than 5%, so no more than 1 adult need correction is a significantly low number of adults requiring eyesight correction?
Your answer would be 6 boxes.
Work:
We will need 3 for each, and there's 24 so we just multiply those two together: 24 x 3 = 72
If there is 12 in each box, and we need 72, we need to find out how many boxes we would need to have enough, even if there's leftovers: 72/12= 6.
So, we will need 6 boxes, and there will be none left over.
Hope I heled!
Answer:
43
Step by step Explanation:
Subtract 33 from 76
76-33=43