Answer:
-2, (-5 is extraneous)
Step-by-step explanation:
assuming √(x+6) -4 =x
√(x+6) = x+4
square both side
x+6 = (x+4)^2
x+6 = x^2+8x+16
x^2+7x+10=0
(x+2)(x+5) = 0
x = -2, -5
put -5 back into org equation and it is not true
√(-5+6) -4 ≠ -5
<span><span><u>Answer</u>
</span>6 goes 8 times into 50 rem 2.<span>
</span><span><u>Explanation</u>
The question you to divide 50 by 6.
It is the only way to get the number of times 6 goes into 50.
50/6=8 Remainder 2
</span>6 goes 8 times into 50<span> rem 2.</span></span><span><span>
</span></span>
<span>1.) d - 1 > -3 and d + 2 < 5
d-1>-3→d-1+1>-3+1→d>-2
</span>d+2<5→d+2-2<5-2→d<3
<span>Part 1: The solution is d>-2 and d<3.
Part 2: There would be an open circle on -2 and an open circle on 3.
Part 3: The shading is between the two numbers.
</span><span>
2.) -3k + 7 > -5 and -7k + 5 < -2
-3k+7>-5→-3k+7-7>-5-7→-3k>-12→(-1/3)(-3k>-12)→k<4
-7k+5<-2→-7k+5-5<-2-5→-7k<-7→(-1/7)(-7k<-7)→k>1
</span>Part 1: The solution is k>1 and k<4.
Part 2: There would be an open circle on 1 and an open circle on 4.
Part 3: The shading is between the two numbers.<span>
3.)-5 < 2y - 3 < 23 (Hint: refer to example 2 in the lesson)
-5<2y-3<23→-5+3<2y-3+3<23+3→-2<2y<26→-2/2<2y/2<26/2→-1<y<13
</span>Part 1: The solution is y>-1 and y<13.
Part 2: There would be an open circle on -1 and an open circle on 13.
Part 3: The shading is between the two numbers.<span>
4.)x - 4 < 5 or x + 2 > 15
x-4<5→x-4+4<5+4→x<9
x+2>15→x+2-2>15-2→x>13
</span>Part 1: The solution is x>9 or x>13.
Part 2: There would be an open circle on 9 and an open circle on 13.
Part 3: The shading is from 9 to the left and from 13 to the right.<span>
5.) 5x - 4 > 6 or -4x + 5 > 1
5x-4>6→5x-4+4>6+4→5x>10→5x/5>10/5→x>2
-4x+5>1→-4x+5-5>1-5→-4x>-4→(-1/4)(-4x>-4)→x<1
</span>Part 1: The solution is x<1 or x>2.
Part 2: There would be an open circle on 1 and an open circle on 2.
Part 3: The shading is from 1 to the left and from 2 to the right.
Answer:
The answer and solution is in the picture