Answer:
In quadrilateral ABCD we have
AC = AD
and AB being the bisector of ∠A.
Now, in ΔABC and ΔABD,
AC = AD
[Given]
AB = AB
[Common]
∠CAB = ∠DAB [∴ AB bisects ∠CAD]
∴ Using SAS criteria, we have
ΔABC ≌ ΔABD.
∴ Corresponding parts of congruent triangles (c.p.c.t) are equal.
∴ BC = BD.
B is correct because looking at the chart there is less sold at South and D because there were more bags sold at west
Answer:
son = 10 , father = 40
Step-by-step explanation:
Let Five years ago the age of son be x years and age of father be 7x years
Present age of son =x+5
Present age of father =7x+5
5 years later their age will (x+10) and (7x+10)
∴7x+10=3(x+10)
7x−3x=20
4x=20
x=5
So, the present age of son=x+5=5+5=10years
and the present age of father=7x+5=35+5=40years
hope it helps you
I’m pretty sure the answer is (2,1)
We are given the equation:
DA - 2qA = B³
Taking 'A' common on the LHS
A(D - 2q) = B³
Dividing both sides by (D - 2q)
A = B³ / (D - 2q)
