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kondor19780726 [428]
2 years ago
5

What is the solution to 3/2b + 5 < 17? Explain How.

Mathematics
2 answers:
jek_recluse [69]2 years ago
8 0
<h3>3/2b + 5 < 17</h3>

<em>We subtract 5 from both sides of the inequality.</em>

<h3>3/2b + 5 - 5 < 17 - 5</h3><h3>3/2 b < 12</h3>

<em>Multiply both sides by 2/3.</em>

<h3>( 2/3) * (3/2b) < (2/3) * 12</h3><h3>b < 8</h3>

<em>Therefore, the </em><em>correct option</em><em> is </em><em>alternative "A".</em>

<em>We would think that it is </em><em>option B,</em><em> but the only difference is that it changes the</em><em> direction of the sign.</em>

Over [174]2 years ago
4 0

Answer:  [A]: " b < 8 " .
_____

Step-by-step explanation:

Given:
Find the solution to:   " 3/2b + 5 < 17 " ; and choose from the answer choices.

So; we have:  

 (3/2)b + 5 < 17  ;

 Now, subtract "5" from each side of this inequality:
 (3/2)b + 5 − 5  <  17 − 5  ;

   To get:
  (3/2)b  <  12 ;

Now, let's multiply Each Side of this inequality by "2" ;

 to get rid of the fraction:

    "  2*(3/2)b  <   12*2 "  ;

{Note: " 2 *\frac{3}{2}=\frac{2}{1}*\frac{3}{2} " } ;

Note:  To simplify:  " \frac{2}{1} * \frac{3}{2} " ;
   Note the "2" in the denominator in the "first term" ;  

   And:  The "2" in the denominator in the "second term" ;

      Both "cancel out" to "1" ;  since:  "[ 2 / 2 = 2÷2 = 1 ]" ;

   And:  we have:  " \frac{1}{1}*\frac{3}{1}= 1 *3 = 3 " };

_____
and rewrite:
   " 3b < 24 "  ;

Now, divide Each side of the inequality by "3" ;

 to isolate "b" on one side of the inequality;

and to solve for "x" ;
_____
 " 3b/3 < 24/3 " ;

 to get:

_____

   " b < 8 " ; which corresponds to the correct answer:

Answer choice:  [A]:  " b < 8 " .
_____

Hope this is helpful to you! Best wishes!
_____

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slader (a) Find parametric equations for the line through (4, 1, 8) that is perpendicular to the plane x − y + 4z = 2. (Use the
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Answer:

(x(t), y(t), z(t)) = (4 + t, 1 - t, 8 + 4t)

xy - plane    (x, y, z) = (2, -1, 0)

yz - plane    (x, y, z) = (0, 5, -8)

xz - plane     (x, y, z) = (5, 0, 12)

Step-by-step explanation:

The given point (x, y ,z) = (4, 1, 8)

The plane x -y + 4z = 2

Normal vector (n) = < 1, -1, 4 >

The equation of line through point (4, 1, 8) and the plane is:

(x(t), y(t), z(t)) = (4, 1, 8) + t(1, -1, 4)

(x(t), y(t), z(t)) = (4 + t, 1 - t, 8 + 4t)

Any point on the line P(x, y, z) = ( 4 + t, 1 - t, 8 + 4t)

xy-Pane ⇒ z = 0

8 + 4t = 0

4t = - 8

t = -8/4

t = -2

∴

(x, y, z) = (4 - 2, 1 - 2, 8 + 4(-2))

(x, y, z) = (2, -1, 0)

yz-plane ⇒ x = 0

4 + t = 0

t = -4

∴

(x, y, z) = (4 + (-4) , 1-(-4), 8 + 4(-4)

(x, y, z) = (0, 5, -8)

xz-plane ⇒ y = 0

1 - t = 0

-t = -1

t = 1

∴

(x, y, z) = ( 4 + 1, 1 - 1, 8 + 4(1) )

(x, y, z) = (5, 0, 12)

6 0
3 years ago
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