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bija089 [108]
3 years ago
8

Which equation best shows that 454545 is a multiple of 151515?

Mathematics
1 answer:
rusak2 [61]3 years ago
7 0
454545/151515 which would be 3 i might be wrong.
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Solve the equation in the complex number system.
tatiyna
To get rid of x^{3}, you have to take the third root of both sides:
\sqrt[3]{x^{3}} = \sqrt[3]{1}
But that won't help you with understanding the problem. It is better to write x^{3}-1 as a product of 2 polynomials:
x^{3}-1 = (x-1)\cdot (x^{2} +x +1)
From this we know, that x-1 = 0 => x = 1 is the solution. Another solutions (complex roots) are the roots of quadratic equation.
3 0
3 years ago
Read 2 more answers
Ok ong i'm struggling and need help i've been up all night- Ill give brainlyest!!
Ipatiy [6.2K]

Answer:

  1. 1
  2. - 9
  3. 13
  4. 15

Step-by-step explanation

- 7(6x-1)+x=36

  1. => 42x - 7 + x = 36
  2. => 43x - 7 = 36
  3. => 43x =  36 + 6 = 43
  4. => x = 43 / 43 = 1

- 11-2(8+3p)=7²

  1. => 11 - 16 - 6p = 7^2
  2. => 11 - 16 - 6p = 49
  3. => -5 - 6p = 49
  4. => -6p = 49 + 5 = 54
  5. => p = (54) / (-6) = - 9

-  1/4(5b+11)=19

  1. => (5/4)b +  (11/4) = 19
  2. => (5/4)b = 19 - (11/4) = 65 /4
  3. => b = (65/4) / (5/4) => (65/4) * (4/5) = 13

- 2/7(4m-18)=12

  1. => (8/7)m - (36/7) = 12
  2. => (8/7)m = 12 + (36/7) = 120/7
  3. => m = (120/7) / (8/7) = 120 /8 = 15

3 0
3 years ago
Each leg of a 45°-45°-90° triangle measures 14 cm. What is the length of the hypotenuse? 7 cm cm 14 cm cm
Mashutka [201]
Check the picture below.

8 0
3 years ago
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Point T is on line segment \overline{SU} SU . Given ST=12ST=12 and TU=3,TU=3, determine the length \overline{SU}. SU
vova2212 [387]

Answer:

SU = 15

Step-by-step explanation:

Given that,

Point T is on line segment SU. So,

SU = ST + TU

Putting all the values, we get :

SU = 12 + 3

SU = 15

Hence, the length of SU is 15 units.

3 0
3 years ago
M(12, 1) is the midpoint of DG. If D is at (6, 5), then where is G?
sukhopar [10]

Answer:

18, -3

using the formula for midpoint M=(x1+x2)/2 ,(y1+y2)/2

4 0
3 years ago
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