Answer:
Parallel line:

Perpendicular line:

Step-by-step explanation:
we are given equation 4x+5y=19
Firstly, we will solve for y

we can change it into y=mx+b form


so,

Parallel line:
we know that slope of two parallel lines are always same
so,

Let's assume parallel line passes through (1,1)
now, we can find equation of line

we can plug values

now, we can solve for y

Perpendicular line:
we know that slope of perpendicular line is -1/m
so, we get slope as

Let's assume perpendicular line passes through (2,2)
now, we can find equation of line

we can plug values

now, we can solve for y

Answer: 1) 0.10
2) 0.60
3) 0.20
4) 0.10
<u>Step-by-step explanation:</u>
The total frequency is 20+120+40+20 = 200. This means they ran the experiment 200 times. The probability distribution is calculated by the satisfactory number of outcomes (frequency) divided by the total number of experiments/outcomes (total frequency):
![\begin{array}{c|c||lc}\underline{x}&\underline{f}&\underline{f\div 200}&\underline{\text{Probability Distribution}}\\1&20&20\div200=&0.10\\2&120&120\div 200=&0.60\\3&40&40\div 200=&0.20\\4&20&20\div 200=&0.10\end{array}\right]](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bc%7Cc%7C%7Clc%7D%5Cunderline%7Bx%7D%26%5Cunderline%7Bf%7D%26%5Cunderline%7Bf%5Cdiv%20200%7D%26%5Cunderline%7B%5Ctext%7BProbability%20Distribution%7D%7D%5C%5C1%2620%2620%5Cdiv200%3D%260.10%5C%5C2%26120%26120%5Cdiv%20200%3D%260.60%5C%5C3%2640%2640%5Cdiv%20200%3D%260.20%5C%5C4%2620%2620%5Cdiv%20200%3D%260.10%5Cend%7Barray%7D%5Cright%5D)
Answer:
tan56°
Step-by-step explanation:
The Addition identity for tangent ratio is
tan(x + y) =
, thus
= tan(24 + 32)° = tan56°
1.56%<span> 1/8 of the original source (25 counts) remains at 3:00pm. This means that the </span>half-life<span> is 1 hour. Continue to find the fraction at 6:00pm.</span>
Answer:
Cos x = 1 -
+
-
+ ...
Step-by-step explanation:
We use Taylor series expansion to answer this question.
We have to find the expansion of cos x at x = 0
f(x) = cos x, f'(x) = -sin x, f''(x) = -cos x, f'''(x) = sin x, f''''(x) = cos x
Now we evaluate them at x = 0.
f(0) = 1, f'(0) = 0, f''(0) = -1, f'''(0) = 0, f''''(0) = 1
Now, by Taylor series expansion we have
f(x) = f(a) + f'(a)(x-a) +
+
+
+ ...
Putting a = 0 and all the values from above in the expansion, we get,
Cos x = 1 -
+
-
+ ...