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tia_tia [17]
4 years ago
7

What is the distance between (2,-1) and (2,5) rounded to the nearest 10th

Mathematics
1 answer:
xxMikexx [17]4 years ago
5 0

Answer:

<h3>             5.0</h3>

Step-by-step explanation:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\d=\sqrt{(2-2)^2+(5+1)^2}=\sqrt{0^2+5^2}=\sqrt{25}=5

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7 is higher than 4, so it rounds up.
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The price for each cd equals 9.95 so I would estimate it to 10$
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Need help with 21-23 you suppose to simplify the expression
lora16 [44]

To solve these problems, we must remember the distributive property. This property states that a coefficient being multiplied by a polynomial in parentheses is equal to the sum of the coefficient times each of the separate terms. Using this knowledge, let's begin with number 21:

-(4x + 17) + 3(7-x)

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-4x - 17 + 21 - 3x

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-7x + 4 (your answer)

Now, we can move on to question 22 and solve it in a similar manner:

7(2n-8) - 4(12 - 8n)

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Combine like terms after that:

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7 0
3 years ago
If $10,000 is invested at an annual rate of 11%, compounded quarterly, find the value of the investment after the given number o
lana [24]

Answer:

a) A\simeq17204.28

b) A\simeq29598.74

c)A\simeq50922.51

Step-by-step explanation:

The amount formula in compound interest is:

A=P(1+\frac{r}{n} )^{nt}

where:

P = principal amount

r = annual interest

n = number of compounding periods

t = number of years

We already know that:

P = $10000

r = 11\% = \frac{11\%}{100\%}=0.11

n = 4 (quarterly in a year)

a ) t = 5 years

A=10000(1+\frac{0.11}{4} )^{(4)(5)}\\\\A=10000(1+\frac{0.11}{4} )^{20}\\\\A=17204.28431\\\\A\simeq17204.28

b) t = 10 years

A=10000(1+\frac{0.11}{4} )^{(4)(10)}\\\\A=10000(1+\frac{0.11}{4} )^{40}\\\\A=29598.73987\\\\A\simeq29598.74

c) t = 15 years

A=10000(1+\frac{0.11}{4} )^{(4)(15)}\\\\A=10000(1+\frac{0.11}{4} )^{60}\\\\A=50922.51361\\\\A\simeq50922.51

5 0
3 years ago
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