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bearhunter [10]
1 year ago
14

What is the image of the point (-7,9) after a rotation of 270 counterclockwise about the origin

Mathematics
1 answer:
erastovalidia [21]1 year ago
8 0
Answer is (9, 7)

Step by step

Rule: 270 degrees counterclockwise about the origin our point A(x,y) becomes A'(y,-x).

This means, we switch x and y and make x negative.

So

(-7, 9) ➡️ ( 9, 7)
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Angel paints three rooms with two gallons of paint. How many rooms can he paint with fifteen gallons of paint?​
Vanyuwa [196]

Answer:

22 rooms

Step-by-step explanation:

If two gallons of paint covers 3 rooms then you need to divide 15 gallons of paint by 2 gallons of paint = 7.5 gallons of paint. then you need to multiply 7.5 gallons of paint by 3 rooms = 22.5..... so that means you can paint 22 full rooms.

6 0
2 years ago
Plsssss
bixtya [17]
3/9 = x/36
Now cross multiply
108 = 9x
X = 12
3 0
2 years ago
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Identify the lower class​ limits, upper class​ limits, class​ width, class​ midpoints, and class boundaries for the given freque
maw [93]

Answer:

The number of individuals included in the summary is 146.

Step-by-step explanation:

The frequency distribution table provided is as follows:

Class Intervals    Frequency

    100 - 199               24

   200 - 299              90

   300 - 399              27

   400 - 499                1

   500 - 599               4

The lower class limit it the smallest value of each class interval.

Lower class limit = {100, 200, 300, 400, 500}

The upper class limit it the highest value of each class interval.

Upper class limit = {199, 299, 399, 499, 599}

The lower class boundaries are the lower class limits decreased by 0.5 and the upper class boundaries are the upper class limits increased by 0.5.

Class boundaries:

   99.5 - 199.5  

  199.5 - 299.5

  299.5 - 399.5

  399.5 - 499.5

  499.5 - 599.5

The class width is the difference between the class boundaries of each class.

Class width = 199.5 - 99.5 = 100

So, the class width is 100.

The midpoints of a class is the average value of the boundaries of a class.

\text{Midpoint}_{100-199}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{99.5+199.5}{2}\\\\=149.5

\text{Midpoint}_{200-299}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{199.5+299.5}{2}\\\\=249.5

\text{Midpoint}_{300-399}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{299.5+399.5}{2}\\\\=349.5

\text{Midpoint}_{400-499}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{399.5+499.5}{2}\\\\=449.5

\text{Midpoint}_{500-599}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{499.5+599.5}{2}\\\\=549.5

The number of individuals included in the summary is the sum of all frequencies.

\text{Number of Individuals}=24 + 90 + 27 + 1 + 4=146

Thus, the number of individuals included in the summary is 146.

3 0
2 years ago
Read 2 more answers
Need help. Please hep
alexandr1967 [171]
Cant see the image can you send it by an email

4 0
3 years ago
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Write −0.312 as a fraction in simplest form.
ZanzabumX [31]

Answer:

-39/125

needs more characters

6 0
3 years ago
Read 2 more answers
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