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Alexus [3.1K]
3 years ago
13

5x-8y+9 what are the terms of the expression? what are the coefficients of the expression

Mathematics
2 answers:
Sladkaya [172]3 years ago
7 0

Answer:

The coefficients are 5,8. The terms of expression are 5x, 8y and 9

frutty [35]3 years ago
6 0

Step-by-step explanation:

The coefficient for the equation is 5 and 8 as both of the numbers have a variable by its side (the letter x & y). Meanwhile the terms for the equation are 5x, -8y, and 9. This is because all those numbers have an operation symbol. Keep in mind that 5x, has a positive operation at the front of the number but it is not written to the equation to make it simpler. Hope this helps ease up your understanding.

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I NEED HELP ASAP PLEASE
Bezzdna [24]
It would be c.

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g 7. Find Re f and Im f and find their values at the given z. (Both answers should be included) f = z⁄(z + 1), z = 4 − 5
Schach [20]

Answer:

The real and imaginary parts of the result are \frac{1441}{1601} and \frac{4}{1601}, respectively.

Step-by-step explanation:

Let be f(z) = \frac{z}{z+1}, the following expression is expanded by algebraic means:

f(z) = \frac{z\cdot (z-1)}{(z+1)\cdot (z-1)}

f(z) = \frac{z^{2}-z}{z^{2}-1}

f(z) = \frac{z^{2}}{z^{2}-1}-\frac{z}{z^{2}-1}

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z^{2} = 41 - i40

Then, the variable is substituted in the equation and simplified:

f(z) = \frac{41-i40}{41-i39} -\frac{4-i5}{41-i39}

f(z) = \frac{37-i35}{41-i39}

f(z) = \frac{(37-i35)\cdot (41+i39)}{(41-i39)\cdot (41+i39)}

f(z) = \frac{1517-i1435+i1443+1365}{3202}

f(z) = \frac{2882+i8}{3202}

f(z) = \frac{1441}{1601} + i\frac{4}{1601}

The real and imaginary parts of the result are \frac{1441}{1601} and \frac{4}{1601}, respectively.

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