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DIA [1.3K]
2 years ago
15

T(x)=−x^+4x−3 Find two points on the graph of the parabola other than the vertex and x-intercepts.

Mathematics
1 answer:
mixer [17]2 years ago
6 0

The points on the graph of the parabola other than the vertex and x-intercepts where the equation of the parabola is given as t(x) = -x^2 + 4x - 3 are (10, -63) and (5, -8)

<h3>How to determine the points on the graph of the parabola other than the vertex and x-intercepts?</h3>

The equation of the parabola is given as:

t(x) = -x^2 + 4x - 3

The vertex of the parabola is the point where the graph is at the maximum or the minimum

While the x-intercept is the point where the graph crosses the x-axis i.e when y = 0

Having said that, we have the equation of the parabola to be

t(x) = -x^2 + 4x - 3

Set x = 5.

So, we have:

t(5) = -5^2 + 4 * 5 - 3

Evaluate the exponents

t(5) = -25 + 4 * 5 - 3

Evaluate the products

t(5) = -25 + 20 - 3

Evaluate the sum and the difference

t(5) = -8

Set x = 10.

So, we have:

t(10) = -10^2 + 4 * 10 - 3

Evaluate the exponents

t(10) = -100 + 4 * 10 - 3

Evaluate the products

t(10) = -100 + 40 - 3

Evaluate the sum and the difference

t(10) = -63

Hence, the points on the graph of the parabola other than the vertex and x-intercepts where the equation of the parabola is given as t(x) = -x^2 + 4x - 3 are (10, -63) and (5, -8)

Read more about parabola at:

brainly.com/question/4061870

#SPJ1

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Answer:

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A chemist wishes to mix a solution that is 6% acid. She has on hand 14 liters of a 4% acid solution and wishes to add some 10% a
jonny [76]

she should add 7 liters of 10% acid solution

Explanation

Step 1

set the equation:

a) let X represents the amount os solution that is 4% acid

let Y represents the amount os solution that is 10% acid

so

I)

\begin{gathered} \frac{4}{100}X+\frac{10}{100}Y=\frac{6}{100}(x+y) \\  \end{gathered}

if he has 14 liters of 4% acid solution

x=14

\begin{gathered} \frac{4}{100}X+\frac{10}{100}Y=\frac{6}{100}(X+Y) \\ \frac{4}{100}*14+\frac{10}{100}Y=\frac{6}{100}(X+Y) \\ 0.56+0.1Y=0.06(14+Y) \\ 0.56+0.1Y=0.84+0.06Y \\  \end{gathered}

Step 2

solve the equation :

\begin{gathered} 0.56+0.1Y=0.84+0.06Y \\ subtract\text{ 0.06Y in both sides} \\ 0.56+0.1Y-0.06Y=0.84+0.06Y-0.06Y \\ 0.56+0.04Y=0.84 \\ subtract\text{ 0.56 in both sides} \\ 0.56+0.04Y-0.56=0.84-0.56 \\ 0.04Y=0.28 \\ divide\text{ both sides by 0.04} \\ \frac{0.04Y}{0.04}=\frac{0.28}{0.04} \\ Y=7 \end{gathered}

therefore,

she should add 7 liters of 10% acid solution

I hope this helps you

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