Table a is 3 b is 2 and c is 1
Start at 4 and since it a negative go down one and over one
(x-9) (x+2)=x²+2x-9x-18=x²-7x-18
(5x+1)² = 7; expand: 25x² + 10x +1 = 7 or 25x² + 10x -6 = 0
Solve this quadratic for x:
x = [-b + √(b² - 4ac)]/2a and x = [-b - √(b² - 4ac)]/2a
Plug the values and you'll find :
x = (- √7 - 1)/5 (answer C)
x = (+√7 -1)/5 (answer E)
