Answer:
Last year Dr. Potter give<u> 32 </u>Polio vaccination and <u>28</u> measles vaccination.
Step-by-step explanation:
Given:
Each Polio vaccination consists of 4 doses , and each measles vaccination consists of 2 doses.
Last year ,Dr. Potter gave a total of 60 vaccinations that consisted of a total of 184 doses.
Now, to find the number of polio vaccinations and many measles vaccination.
Let the number of Polio vaccination be ![x.](https://tex.z-dn.net/?f=x.)
And let the number of measles vaccination be ![y.](https://tex.z-dn.net/?f=y.)
So, the total number of vaccinations:
![x+y=60](https://tex.z-dn.net/?f=x%2By%3D60)
.......(1)
<em>As, given each Polio vaccination consists of 4 doses , and each measles vaccination consists of 2 doses.</em>
Thus, the total number of doses:
![4x+2y=184](https://tex.z-dn.net/?f=4x%2B2y%3D184)
Substituting the value of
from equation (1):
![4x+2(60-x)=184](https://tex.z-dn.net/?f=4x%2B2%2860-x%29%3D184)
![4x+120-2x=184](https://tex.z-dn.net/?f=4x%2B120-2x%3D184)
![2x+120=184](https://tex.z-dn.net/?f=2x%2B120%3D184)
<em>Subtracting both sides by 120 we get:</em>
![2x=64](https://tex.z-dn.net/?f=2x%3D64)
<em>Dividing both sides by 2 we get:</em>
![x=32.](https://tex.z-dn.net/?f=x%3D32.)
<em>The number of Polio vaccination = 32.</em>
Now, putting the value of
in equation (1):
![y=60-x](https://tex.z-dn.net/?f=y%3D60-x)
![y=60-32](https://tex.z-dn.net/?f=y%3D60-32)
![y=28.](https://tex.z-dn.net/?f=y%3D28.)
<em>The number of measles vaccination = 28.</em>
Therefore, last year Dr. Potter give 32 Polio vaccination and 28 measles vaccination.