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1 year ago

A student performed the following steps to find the solution to the equation

Mathematics

1 answer:

rusak2 [61]1 year ago

3 0

Answer:

Step-by-step explanation:

step 2 : x + 3 = 0 and x - 5 = 0 ← correct

step 3

x = 3 and x = - 5 ← error made here with signs, correct statement should be

x + 3 = 0 ⇒ x = - 3

x - 5 = 0 ⇒ x = 5

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Free_Kalibri [48]

Answer:

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Step-by-step explanation:

Given the expression

$\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}$

solving the expression

$\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}$

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$2\sqrt{x^3y^4}=2xy^2\sqrt{x}$

so the expression becomes

$\:\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=xy\sqrt{y}+2xy^2\sqrt{x}+xy\sqrt{y}$

Group like terms

$=2xy^2\sqrt{x}+xy\sqrt{y}+xy\sqrt{y}$

Add similar elements

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Therefore, we conclude that:

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Read 2 more answers

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Step-by-step explanation:

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