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STatiana [176]
2 years ago
7

When a 10-kg block is simultaneously pushed toward the east with 20 n and toward the west with 15 n, the combination of these fo

rces on the block is?
Physics
1 answer:
uysha [10]2 years ago
8 0

When a 10-kg block is simultaneously pushed toward the east with 20N and toward the west with 15N, the combination of these forces on the block is 5N toward the East

Let's understand this problem in detail

Let F_{1} = 20N which is in east direction

and F_{2} = 15N which is acting in the west direction

Now, F_{net} = F_{1} + F_{2}

But F_{1} and F_{2} are in opposite direction.

So let's rotate the force vector F_{2} by 180 degrees which becomes -F_{2}

Now both F_{1} and F_{2} are in same directionof the forces are in a single line

Adding both of them, we get

F_{net} = F_{1} + (-F_{2})

F_{net} = 20N - 15N = 5N, as both of the forces are in east direction hence, the net force is also acting in the east driection

Learn more about forces here

brainly.com/question/13191643

#SPJ4

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Answer:

a. Disk, 28 thousand light-years from

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Since, a galactic disc is a component of disc galaxies, for instance spiral galaxies and lenticular galaxies. It consists of a stellar component and a gaseous component.

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The Sun is located about 26,000 light-years away from the centre of the galaxy.

∵ From the given options 28,000 is nearest to 26,000

Hence, the sun is about 28 thousand light-years from the centre of the galaxy.

i.e. OPTION 'a' would be correct.

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Winds are named based on different factors. How are winds usually named?
eduard
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3 years ago
A kettle is rated at 1 kW, 220 V. Calculate the working resistance of the kettle.
Anna [14]

Explanation:

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Voltage, V = 220 V

(a) Electric power is given by the formula as follows :

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R is resistance

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(b) When connected to a 220 V supply, it takes 3 minutes for the water in the kettle to reach boiling point.

Energy supplied is given by :

E=P\times t

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5 0
3 years ago
A ski gondola is connected to the top of a hill by a steel cable of length 620 m and diameter 1.5 cm. As the gondola comes to th
xz_007 [3.2K]

Answer:

(a) 89 m/s

(b) 11000 N

Explanation:

Note that answers are given to 2 significant figures which is what we have in the values in the question.

(a) Speed is given by the ratio of distance to time. In the question, the time given was the time it took the pulse to travel the length of the cable twice. Thus, the distance travelled is twice the length of the cable.

v=\dfrac{2\times 620 \text{ m}}{14\text{ s}} = \dfrac{1240\text{ m}}{14\text{ s}}=88.571428\ldots \text{ m/s}= 89\text{ m/s}

(b) The tension, T, is given by

v =\sqrt{\dfrac{T}{\mu}}

where v is the speed, T is the tension and \mu is the mass per unit length.

Hence,

T = \mu\cdot v^{2}

To determine \mu, we need to know the mass of the cable. We use the density formula:

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If the length is denoted by l, then

\mu = \dfrac{m}{l} = \dfrac{\rho\cdot V}{l}

T = \dfrac{\rho\cdot V}{l} v^{2}

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The cable is approximately a cylinder with diameter 1.5 cm and length or height of 620 m. Its volume is

V = \pi \dfrac{d^{2}}{4} l

T = \dfrac{\rho\cdot\pi d^2 l}{4l}v^2 = \dfrac{\rho\cdot\pi d^2}{4}v^2

T = \dfrac{8050\times\pi\times0.015^2}{4} \times 88.57^2

T = 11159.4186\ldots \text{ N} = 11000 \text{ N}

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