Answer:
please find attached file
Explanation:
The weight of a block on the inclined plane is 500 N and the angle of incline is 30 degrees. What is the magnitude of the force
of friction for static equilibrium? What is the normal force of the surface pushing up on the block?
1 answer:
Answer:
250 N
433 N
Explanation:
N = Normal force by the surface of the inclined plane
W = Weight of the block = 500 N
f = static frictional force acting on the block
Parallel to incline, force equation is given as
f = W Sin30
f = (500) Sin30
f = 250 N
Perpendicular to incline force equation is given
N = W Cos30
N = (500) Cos30
N = 433 N
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Answer:
The emf in the inductor continues to be zero.
Explanation:
It is given that, an inductor with no resistance carries a constant current. Then the current is brought to a new constant value twice as large. Finally, the current is constant at its higher value. We know that the voltage across the inductor is given by :
is the change in current
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