Question

An object is thrown directly up (positive direction) with a velocity (vo) of 20.0 m/s and do= 0. How high does it rise (v = 0 cm/s at top of rise). Remember, acceleration is -9.80 m/s2.
d = _____ m

1.02
2.04
20.4
40.8

Answer 1

Answer:

20.4

Explanation:

Given:

y₀ = 0 m

v₀ = 20.0 m/s

v = 0 m/s

a = -9.80 m/s²

Find: y

v² = v₀² + 2a (y − y₀)

(0 m/s)² = (20.0 m/s)² + 2 (-9.80 m/s²) (y − 0 m)

y = 20.4 m