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Nat2105 [25]
3 years ago
8

An object is thrown directly up (positive direction) with a velocity (vo) of 20.0 m/s and do= 0. How high does it rise (v = 0 cm

/s at top of rise). Remember, acceleration is -9.80 m/s2.
d = _____ m

1.02
2.04
20.4
40.8
Physics
1 answer:
cluponka [151]3 years ago
3 0

Answer:

20.4

Explanation:

Given:

y₀ = 0 m

v₀ = 20.0 m/s

v = 0 m/s

a = -9.80 m/s²

Find: y

v² = v₀² + 2a (y − y₀)

(0 m/s)² = (20.0 m/s)² + 2 (-9.80 m/s²) (y − 0 m)

y = 20.4 m

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A capacitor has plates of area 8.25 * 10 ^ - 5 m ^ 2 . To create a capacitance of 3.35*10^ -10 F , how far apart should the plates be ?

Explanation:

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In a simple model of the hydrogen atom, the electron moves in a circular orbit of radius 0.053nm around a stationary proton. par
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<span>Here the force that is applied between the electron and proton is centripetal, so equate the two forces to determine the velocity.
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0. The volume of a cube is 27cm3. Find the length of edge of cube.​
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Explanation:

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3 0
3 years ago
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A resistor with an unknown resistance is connected in parallel to a 13 Ω resistor. When both resistors are connected in parallel
larisa86 [58]

Answer:

R2 = 10.31Ω

Explanation:

For two resistors in parallel you have that the equivalent resistance is:

\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}\\\\      (1)

R1 =  13 Ω

R2 = ?

The equivalent resistance of the circuit can also be calculated by using the Ohm's law:

I=\frac{V}{R_{eq}}\\\\R_{eq}=\frac{V}{I}            (2)

V: emf source voltage = 23 V

I: current = 4 A

You calculate the Req by using the equation (2):

R_{eq}=\frac{23V}{4A}=5.75\Omega

Now, you can calculate the unknown resistor R2 by using the equation (1):

\frac{1}{R_2}=\frac{1}{R_{eq}}-\frac{1}{R_1}\\\\R_2=\frac{R_{eq}R_1}{R_1-R_{eq}}\\\\R_2=\frac{(5.75\Omega)(13\Omega)}{13\Omega-5.75\Omega}=10.31\Omega

hence, the resistance of the unknown resistor is 10.31Ω

8 0
3 years ago
Read 2 more answers
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