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3 years ago

the length of a rectangle is twice its width the perimeter is 48 cm what are the dimensions of the rectangle

Mathematics

2 answers:

inysia [295]3 years ago

5 0

Answer:

The length=16cm and the width=8cm.

Step-by-step explanation:

Given that the length is twice the breadth or width of the rectangle

Let's assume that the breadth of the rectangle is x.

Thus the length is 2x.

Given perimeter=48cm

The formula for the perimeter of a rectangle is 2(l+b) where l is length and b is breadth.

2(x+2x)=48

(3x)=48/2

3x=24

x=8cm

2x=16cm

avanturin [10]3 years ago

3 0

Step-by-step explanation:

length=2x

width=x

2x+x+2x+x=48

6x=48

6x÷6=48÷6

x=8

length=16

width=8

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2 years ago

A box of oranges weighs 4kg. if one orange weighs 80 g how many oranges are in the box?

wlad13 [49]

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3 years ago

Read 2 more answers

A. Sam purchased 3 games for $140 after a discount of 30%. What was the original price?

Semmy [17]

Answer:

a) $175 b) It will be $126

Step-by-step explanation:

Cost price of 3 games= $140

Let the original price of games= $ x

Discount is given= 30%

According to question

x $\frac{(100-20)}{100}$ = $140

x $\frac{80}{100}$ = $140

x ×0.8= $140

x= $ $\frac{$140}{0.8}$

x= $175

Hence, the original price of games $ 140

(b) If Sam had given a discount of 20%

Again a discount = 10%

The price of games=$ 140

Now, the selling price will be= 175 $\frac{(100-20)}{100}$ × $\frac{(100-10)}{100}$

Now, the selling price will be= $ 126

Hence, the price will be different.

7 0

4 years ago

9. In a rhombus whose side measures 34 and the smaller angle is 42°. Find the length of the larger diagonal, to the nearest tent

Veseljchak [2.6K]

Answer:

63.5

Step-by-step explanation:

The diagonals of a rhombus bisect opposite angles.

The longer diagonal bisects the 42° angle

The larger angle of the rhombus is 180 - 42 = 138

Let x = the length of the longer diagonal

You know two sides and the included angle of a triangle.

Using the law of cosines we get

$x^{2} = 34^{2} + 34^{2} -2(34)(34) cos 138\\ = 1156 + 1156 - 2312 cos 138\\ = 4030.150837...\\x = \sqrt{4030.150837} = 63.48$ $x^{2} = 34^{2} + 34^{2} -2(34)(34)cos 138\\ = 1156 + 1156 - 2312 cos 138\\ = 4030.1508...\\ x = \sqrt{4030.1508} \\ = 63.48$ x^2 = 34^2 + 34^2 - 2(34)(34) cos 138

= 1156 + 1156 - 2312 c0s 138

= 4030.1508...

x = sq rt 4030.1508...

= 63.5

7 0

3 years ago