Question

Following calculus questions. Thanks so much

Answer 1

The vertical asymptote of the function that are illustrated in the calculus and the function y = 3cot(1/2x) - 4 will be:

B. x = 0

C. x = +-2π

How to illustrate the information?

It should be noted that the function that's given from the information illustrated is given as:

y = 3 for (x/2) - 4

It should be noted that there is no phase shift and the period is 2π.

It should be noted that the vertical asymptote will be x = 3πn where no is represented as the integer at n = 0, 1, and -1.

Therefore, the vertical asymptote of the function that are illustrated in the calculus and the function y = 3cot(1/2x) - 4 will be x = 0 and x = +2π.

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