All the answers are correct.
Answer:
D, 49.42
Step-by-step explanation:
ΔVFT=180-90-43=47
formula
a/sin A = b/sin B/ = c/sin C
So,
FV/sin90=53/sin47
FV=72.4684
FT=√(72.4684)^2-(53)^2
FT=49.4234
Ans:D
Answer:
1. B) 5.7
2. A) 12
3. A) 11.4
4. A) 5.7
5. A) 16.2
6. A) 11.2
7. No, they do not form a right triangle
8. Yes, they do form a right triangle
Step-by-step explanation:
Extra tip: The hypotenuse has to be less than both sides added together, but cannot be more than either of the sides alone.
1.
16² + b² = 17²
256 + b² = 289
256 - 256 + b² = 289 - 256
b² = 33
√b² = √33
b = 5.74 or 5.7
2.
16² + b² = 20²
256 + b² = 400
256 - 256 + b² = 400 - 256
b² = 144
√b² = √144
b = 12
3.
7² + 9² = c²
49 + 81 = c²
130 = c²
√130 = √c²
11.40 or 11.4 = c
4.
7² + b² = 9²
49 + b² = 81
49 - 49 + b² = 81 - 49
b² = 32
√b² = √32
b = 5.65 or 5.7
5.
a² + 5² = 17²
a² + 25 = 289
a² + 25 - 25 = 289 - 25
a² = 264
√a² = √264
a = 16.24 or 16.2
6.
10² + b² = 15²
100 + b² = 225
100 - 100 + b² = 225 - 100
b² = 125
√b² = √125
b = 11.18 or 11.2
7.
15² + 8² = 16²
225 + 64 = 256
289 ≠ 256
8.
5² + 12² = 13²
25 + 144 = 169
169 = 169
The answer is 6 units and 3 fourths
Let 
. The tangent plane to the surface at (0, 0, 8) is
The gradient is
so the tangent plane's equation is
The normal vector to the plane at (0, 0, 8) is the same as the gradient of the surface at this point, (1, 1, 1). We can get all points along the line containing this vector by scaling the vector by 
, then ensure it passes through (0, 0, 8) by translating the line so that it does. Then the line has parametric equation
or 
, 
, and 
.
(See the attached plot; the given surface is orange, (0, 0, 8) is the black point, the tangent plane is blue, and the red line is the normal at this point)
