The expanded logarithm of log 2 x³y⁻² is = log 3 + 3 log x - 2 log y.
What is a logarithmic function?
A logarithmic function in mathematics is defined as the function which is the inverse of the exponential function. It is denoted by using the word log. For example log 10 = 1
Expanding the given logarithm: log 2 x³y⁻²
Given logarithmic expression is log 2 x³y⁻²
Applying given properties of logarithmic function;
log a + log b = log (ab)
2 log a = log a^2
Now, log 2 x³y⁻² = log 3 + log x³ + log y⁻²
= log 3 + 3 log x - 2 log y
Hence, the expanded logarithm of log 2 x³y⁻² is = log 3 + 3 log x - 2 log y.
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Answer:
a trend line can be used to make predictions in real-world situations (the third option)
Explanation:
the first & second options are wrong because it is not a requirement for a trend line to pass through any given data point.
the fourth option is wrong because a trend line shows the general upward/downward trend of the data, and may not necessarily touch all of the data points.
the third option is correct because a trend line helps to roughly estimate the trend (hence the name) of the graph, which allows us to make predictions in real-world situations.
i hope this helps! :D
Answer:
9 2/5
Step-by-step explanation:
6 38/45 + 2 5/9
6 38/45 + 2 25/45 = 8 63/45 = 9 18/45 = 9 2/5
We know that<span>
<span>Figures can be proven similar if one, or more,
similarity transformations (reflections, translations, rotations, dilations)
can be found that map one figure onto another.
In this problem to prove circle 1 and circle 2 are similar, a
translation and a scale factor (from a dilation) will be found to map one
circle onto another.
we have that</span>
<span> Circle 1 is centered at (5,8) and has a
radius of 8 centimeters
Circle 2 is centered at (1,-2) and has a radius of 4 centimeters
</span>
step 1
<span>Move the center of the circle 1 onto the
center of the circle 2
the transformation has the following rule</span>
(x,y)--------> (x-4,y-10)
so
(5,8)------> (5-4,8-10)-----> (1,-2)
so
center circle 1 is now equal to center circle 2
<span>The circles are now concentric (they have the
same center)
</span>
step 2
<span>A dilation is needed to decrease the size of
circle 1 to coincide with circle 2
</span>
scale factor=radius circle 2/radius circle
1-----> 4/8----> 0.5
radius circle 1 will be=8*scale factor-----> 8*0.5-----> 4 cm
radius circle 1 is now equal
to radius circle 2
<span>A
translation, followed by a dilation will map one circle onto the other,
thus proving that the circles are similar
the answer is
</span></span>The circles are similar because you can translate Circle 1 using the transformation rule (x-4,y-10) and then dilate it using a scale factor of (0.5)
