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neonofarm [45]
3 years ago
6

Can anyone help me with this question

Mathematics
1 answer:
GREYUIT [131]3 years ago
8 0
Reflect the triangle across the y-axis. Next translate it 2 units to the left. Then translate it 6 units down.
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Your family is traveling to Mexico on vacation. You have
ycow [4]

Answer:

5960 pesos

Step-by-step explanation:

We can write a proportion

298 pesos --- $25

x pesos      --- $500

x=298*500/25 = 298*20 = 5960 pesos

8 0
3 years ago
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If 62% of 80 classmates like hip-hop, but 70% of 60 relatives like hip-hop, which one is more?
SIZIF [17.4K]

62 percent of 80 is more

Step-by-step explanation:

the 62 percent of 80 comes out to 49.6 people and the other one comes out to 42 people

i dont know how to explain how to do it

8 0
2 years ago
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Use triangle ABC drawn below & only the sides labeled. Find the side of length AB in terms of side a, side b & angle C o
Brrunno [24]

Answer:

AB = \sqrt{a^2 + b^2-2abCos\ C}

Step-by-step explanation:

Given:

The above triangle

Required

Solve for AB in terms of a, b and angle C

Considering right angled triangle BOC where O is the point between b-x and x

From BOC, we have that:

Sin\ C = \frac{h}{a}

Make h the subject:

h = aSin\ C

Also, in BOC (Using Pythagoras)

a^2 = h^2 + x^2

Make x^2 the subject

x^2 = a^2 - h^2

Substitute aSin\ C for h

x^2 = a^2 - h^2 becomes

x^2 = a^2 - (aSin\ C)^2

x^2 = a^2 - a^2Sin^2\ C

Factorize

x^2 = a^2 (1 - Sin^2\ C)

In trigonometry:

Cos^2C = 1-Sin^2C

So, we have that:

x^2 = a^2 Cos^2\ C

Take square roots of both sides

x= aCos\ C

In triangle BOA, applying Pythagoras theorem, we have that:

AB^2 = h^2 + (b-x)^2

Open bracket

AB^2 = h^2 + b^2-2bx+x^2

Substitute x= aCos\ C and h = aSin\ C in AB^2 = h^2 + b^2-2bx+x^2

AB^2 = h^2 + b^2-2bx+x^2

AB^2 = (aSin\ C)^2 + b^2-2b(aCos\ C)+(aCos\ C)^2

Open Bracket

AB^2 = a^2Sin^2\ C + b^2-2abCos\ C+a^2Cos^2\ C

Reorder

AB^2 = a^2Sin^2\ C +a^2Cos^2\ C + b^2-2abCos\ C

Factorize:

AB^2 = a^2(Sin^2\ C +Cos^2\ C) + b^2-2abCos\ C

In trigonometry:

Sin^2C + Cos^2 = 1

So, we have that:

AB^2 = a^2 * 1 + b^2-2abCos\ C

AB^2 = a^2 + b^2-2abCos\ C

Take square roots of both sides

AB = \sqrt{a^2 + b^2-2abCos\ C}

6 0
3 years ago
15 is what percent of<br> 600?<br> Pls show work
chubhunter [2.5K]

Answer:

90

Step-by-step explanation:

600(.15) = 90

8 0
2 years ago
Read 2 more answers
If the radius of a cone is 2 and the height is 4 what is the volume
laila [671]
Your answer: V≈16.76
4 0
3 years ago
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