Chapter : Algebra
Study : Math in Junior high school
x = 7 + √40
find √x of √x + 1
= √x + 1
= √(7+√40) + 1
in Formula is :
= √7+√40 = √x + √y
= (√7+√40)² = (√x + √y)²
= 7+√40 = x + 2√xy + y
= 7 + √40 = x + y + 2√xy
→ 7 = x + y → y = 7 - x ... Equation 1
→ √40 = 2√xy → √40 = 2.2√10 = 4√10
= xy = 10 ... Equation 2
substitution Equation 1 to 2 :
= xy = 10
= x(7-x) = 10
= 7x - x² = 10
= x² - 7x + 10 = 0
= (x - 5)(x - 2) = 0
= x = 5 or x = 2
Subsitution x = 5 and x = 2, to equation 1
#For x = 5
= y = 7 - x
= y = 7 - (5)
= y = 2
#For x = 2
= y = 7 - x
= y = 7 - (2)
= y = 5
and his x and y was find :
#Equation 1 :
= x = 5 and y = 2
#Equation 2 :
= x = 2 and y = 5
So that :
√7+√40 = √x + √y
= √7+√40 = √2 + √5
And that is answer of question :
= √2 + √5 + 1
Answer:
c
Step-by-step explanation:
Pythagoras theroem
= 4√73
Not sure what you're asking. are you wanting to solve 5 ( a - b), where b equals those two things listed below? If that's the case, I can definitely help. If not, please clarify.
Answer:
3x + 6y
Step-by-step explanation:
CLT
<em><u>9</u></em><em><u>x</u></em><em><u>-</u></em><em><u>7</u></em><em><u>x</u></em><em><u>+</u></em><em><u>x</u></em><em><u>+</u></em><em><u>3</u></em><em><u>y</u></em><em><u>-</u></em><em><u>2</u></em><em><u>y</u></em><em><u>+</u></em><em><u>5</u></em><em><u>y</u></em>
<em><u>3</u></em><em><u>x</u></em><em><u>+</u></em><em><u>6</u></em><em><u>y</u></em>
