3 years ago

Divide.(10a^4-5a^3) / 5a

Mathematics

1 answer:

wolverine [178]3 years ago

5 0

$\boxed{\frac{10a^4-5a^3}{ 5a}=\frac{10a^4}{5a}-\frac{5a^3}{5a}=2a^3-a^2}$

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If triangle ABC defined by the coordinates A(1,1), B(9,1), C(1,9) is dilated by a scale factor of 1/2

alukav5142 [94]

Answer:

The transformed points of the triangle ABC are $A' (x,y) = \left( \frac{1}{2}, \frac{1}{2}\right)$ , $B'(x,y) = \left(\frac{9}{2}, \frac{1}{2} \right)$ , $C'(x,y) = \left(\frac{1}{2}, \frac{9}{2}\right)$

Step-by-step explanation:

The new points after applying the scale factor are, respectively:

$A' (x,y) = \frac{1}{2}\cdot (1,1)$

$A' (x,y) = \left( \frac{1}{2}, \frac{1}{2}\right)$

$B' (x,y) = \frac{1}{2}\cdot (9,1)$

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$C'(x,y) = \left(\frac{1}{2}, \frac{9}{2}\right)$

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3 years ago

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Tatiana [17]

Answer:

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Step-by-step explanation:

Because when you substitute X by (-2)

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3 years ago

Read 2 more answers

Whats the the answer -x/3 = 2

Kisachek [45]

Answer:

-6

Step-by-step explanation:

-x/3=2

Multiply both sides by 3:

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Divide both sides by -1:

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Hope this helps!

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Answer:

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Step-by-step explanation:

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Mnenie [13.5K]

55.44

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