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1 year ago

How would you write 6 × 6 × 6 × 6 as an exponential expression?

Mathematics

1 answer:

Dimas [21]1 year ago

3 0

6 and a 4 on the top beside it

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Can u help me on number 5,6,and 7 i will help u on what u need just send me a message

Fynjy0 [20]

5. Input 5 where the x's, 3 = 2(5) - 7 is a true statement. 10 - 7 = 3
3 < 10 - 9 is a false statement, 3 > 1 is a true statement
2 is less than or equal to 11, is a false statement (2 is less than 11, but not equal to)
18 = 30 -12 is a true statement 30 - 12 = 18, 18=18
3= 2 + 5 is a false statement, 3 is not equal to 7

6. 7 is less than or equal to 5(4) -16, 20 - 16 = 4, 7 is not less than or equal to 4. Therefore, 4 is not a solution.

7. 9(5) - 3 < 60, 45-3 < 60, 42 < 60, 42 is less than 60, so the equation is true.
9(6) - 3 < 60, 54 - 3 < 60, 51 < 60, 51 is less than 60, so the equation is true.
6(7) - 3 < 60, 63 -3 < 60, 60 < 60, 60 is equal to 60, the equation is false.

4 0

3 years ago

Read 2 more answers

find all possible value of the given variable

mamaluj [8]

$1.\\ \\ h^2+5h=0 \\ \\h(x+5)=0\\ \\x=0 \ \ \ or \ \ \ x+5 =0\ \ |-5\\ \\x+5-5=0-5\\ \\x=0 \ \ \ or \ \ \ x=-5$

$2.\\ \\ z^2-z=0\\ \\z(x-1)=0\\ \\z=0 \ \ \ or \ \ \ z-1 =0 \ \ | +1\\ \\z-1+1 =0 +1 \\ \\x=0 \ \ \ or \ \ \ z=1$

$3.\\ \\m^2+13m+40=0 \\ \\a=1 ,\ b=13, \ c=40 \\ \\\Delta =b^2-4ac =13^2-4\cdot 1\cdot 40=169 - 1600=-1431 \\ \\and \ we \ know \ when \ \Delta \ is \ negative, \ theres \ no \solution$

$4.\\ \\z^2-3z=0 \\ \\ (z-3)=0\\ \\z=0 \ \ \ or \ \ \ z-3 =0\ \ |+3\\ \\ z-3+3=0+3\\ \\z=0 \ \ \ or \ \ \ z=3$

$5.\\ \\q^2+7q=0 \\ \\q(q+7)=0\\ \\q=0 \ \ \ or \ \ \ q+7 =0\ \ |-7\\ \\q+7-7=0-7\\ \\q=0 \ \ \ or \ \ \ q=-7$

$6.\\ \\k^2+2k=0\\ \\k(k+2)=0\\ \\k=0 \ \ \ or \ \ \ k+2 =0\ \ |-2\\ \\k+2-2=0-2\\ \\k=0 \ \ \ or \ \ \ k=-2$

$7. \\ \\ x^2-3x-70=0 \\ \\a=1,\ b=-3, \ c=-70 \\ \\\Delta =b^2-4ac = (-3)^2-4\cdot 1\cdot (-70)= 9+280=289\\ \\ x_{1}=\frac{-b-\sqrt{\Delta} }{2a}=\frac{3-\sqrt{289}}{2 }=\frac{ 3-17}{2}=\frac{-14}{2}=-7$

$x_{2}=\frac{-b+\sqrt{\Delta} }{2a}=\frac{3+\sqrt{289}}{2 }=\frac{ 3+17}{2}=\frac{20}{2}=10\\ \\(x+7)(x-10)=0$

$8.\\ \\q^2+7q-60=0 \\ \\a=1,\ b=7, \ q=-60 \\ \\\Delta =b^2-4ac = 7^2-4\cdot 1\cdot (-60)=49+240=289 \\ \\ x_{1}=\frac{-b-\sqrt{\Delta} }{2a}=\frac{-7-\sqrt{289}}{2 }=\frac{ -7-17}{2}=\frac{-24}{2}=-12$

$x_{2}=\frac{-b+\sqrt{\Delta} }{2a}=\frac{-7+\sqrt{289}}{2 }=\frac{ -7+17}{2}=\frac{ 10}{2}= 5\\ \\(x+12)(x-5)=0$

$9.\\ \\z^2+9z-36=0 \\ \\a=1,\ b=9, \ q=-36 \\ \\\Delta =b^2-4ac = 9^2-4\cdot 1\cdot (-36)= 81+144=225\\ \\ x_{1}=\frac{-b-\sqrt{\Delta} }{2a}=\frac{-9-\sqrt{225}}{2 }=\frac{ -9-15}{2}=\frac{-24}{2}=-12$

$x_{2}=\frac{-b+\sqrt{\Delta} }{2a}=\frac{-9+\sqrt{225}}{2 }=\frac{ -9+15}{2}=\frac{6}{2}=3\\ \\(x+11)(x-3)=0$

$10.\\ \\d^2-13d+22=0 \\ \\a=1,\ b=-13, \ q=22 \\ \\\Delta =b^2-4ac = (-13)^2-4\cdot 1\cdot 22= 169-88=81\\ \\ d_{1}=\frac{-b-\sqrt{\Delta} }{2a}=\frac{13-\sqrt{81}}{2 }=\frac{ 13-9}{2}=\frac{4}{2}=2$

$d_{2}=\frac{-b+\sqrt{\Delta} }{2a}=\frac{13+\sqrt{81}}{2 }=\frac{ 13+9}{2}=\frac{22}{2}=11\\ \\(d-2)(d-11)=0$

7 0

3 years ago

Steve can jog 14 miles in 2 hours. At this rate, how many miles can he jog in 1/4 hour?

Assoli18 [71]

Answer:

1 3/4 miles in 1/4 hour.

Step-by-step explanation:

Write and solve an equation of ratios:

x (1/4) hr

--------- = ------------

14 mi 2 hr

Cross multiplying, we get 2x = (1/4)(14), or

x = (1/4)(7), or x = 7/4

Steve can jog 7/4 miles in 1/4 hour. That's 1 3/4 miles in 1/4 hour.

4 0

2 years ago

Read 2 more answers

F(0) = 2 and f(2) = 4

RUDIKE [14]

Answer:

Use the slope formula and slope-intercept form

to find the equation.

(

)

−

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

10=z+6 Plz help me with this

garik1379 [7]

Answer:

z=4

Step-by-step explanation:

6+4=10

6 0

3 years ago