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Oksi-84 [34.3K]
3 years ago
13

Evan measured a line to be 20.4 inches long. If the actual length of the line is 19.6

Mathematics
1 answer:
e-lub [12.9K]3 years ago
8 0

Answer:

4.08%

Step-by-step explanation:

% error = error/actual length × 100

Error = 20.4-19.6

= 0.8

% error = 0.8/19.6 × 100

= 4.08%

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Which equation has infinite solutions?
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Answer:

a 3x-7=12x

Step-by-step explanation:

=6.33333333

5 0
3 years ago
If a 100.8 kg cement bag had 20.35 kg removed from it, what is the new weight of the bag?
Snowcat [4.5K]
Just subtract 20.35 from 100.8
100.8 \: kg - 20.35 \: kg = 80.45 \: kg

if your bag weighs 100.8 kg and you scoop out 20.35 kg then weigh your bag it will be 80.45 bc u took out 20.35 kg of the cement to use. hope that explains it
8 0
3 years ago
(FIRST TO ANSWER GETS BRAINLIEST OR 5 STARS) For consecutive weeks, the manager of a local restaurant collected data on the numb
Sergio039 [100]

Yes, the line can be used to make reasonable predictions of the number of cheese pizzas that would be sold in the upcoming weeks. This is because the line is the line of best fit

<h3>Line of best fit </h3>

From the question, we are to determine if the line can be used to make reasonable predictions of the number of cheese pizzas that would be sold in the upcoming weeks

In the graph, we have a scatterplot.

The line drawn is the <u>line of best fit</u>

Hence,

Yes, the line can be used to make reasonable predictions of the number of cheese pizzas that would be sold in the upcoming weeks. This is because the line is the line of best fit.

Learn more on Line of best fit here: brainly.com/question/1564293

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4 0
2 years ago
During one season, a basketball player made 353 of 765 free throws. At that rate, how many free throws would the player make in
telo118 [61]
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3 0
2 years ago
NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h(t) = -4.9t^2
Sauron [17]

Answer:

A.) 24.08 seconds

B.) 825.42 metres

Step-by-step explanation:

function of time is given as

h ( t ) = − 4.9 t 2 + 118 t + 115 .

Where a = -4.9, b = 118, c = 115

Let's assume that the trajectory of the rocket is a perfect parabola.

The time t the rocket will reach its maximum height will be at the symmetry of the parabola.

t = -b/2a

Substitute b and a into the formula

t = -118/-2(4.9)

t = 118/9.8

t = 12.041 seconds

Since NASA launches the rocket at t = 0 seconds, the time it will splash down into the ocean will be 2t.

2t = 2 × 12.041 = 24.08 seconds

Therefore, the rocket splashes down after 24.08 seconds.

B.) At maximum height, time t = 12.041s

Substitute t for 12.041 in the function

h ( t ) = − 4.9 t 2 + 118 t + 115

h(t) = -4.9(12.041)^2 + 118(12.041) + 115

h(t) = -4.9(144.98) + 118(12.041) + 115

h(t) = -710.402 + 1420.82 + 115

h(t) = 825.42 metres

Therefore, the rocket get to the peak at 825.42 metres

6 0
4 years ago
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