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2 years ago

Evan measured a line to be 20.4 inches long. If the actual length of the line is 19.6

Mathematics

1 answer:

e-lub [12.9K]2 years ago

8 0

Answer:

4.08%

Step-by-step explanation:

% error = error/actual length × 100

Error = 20.4-19.6

= 0.8

% error = 0.8/19.6 × 100

= 4.08%

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A car's speedometer has a percent error of 5%. The speedometer currently shows that the car is traveling at a speed of 60 mph.

Minchanka [31]

Answer:

The actual speed of the car is either 57 mph or 63 mph

Step-by-step explanation:

Given as :

The measured speed o the car = 60 mph

The percentage error in speedometer = 5 %

Let The actual speed of car = x mph

Now, percentage error = $\dfrac{\textrm actual value - \textrm measured value}{\textrm measured value}$ × 100

So, $\frac{5}{100}$ = $\frac{x - 60}{60}$

or, $\frac{5}{100}$ × 60 = x - 60

Or, 3 = x - 60

∴ x = 63 mph

Hence The actual speed of the car is either 57 mph or 63 mph . Answer

8 0

3 years ago

Choose the values of the range given the function below. {(-1, -3), (5,7). (8. -4), (-7, 3), (-5, 11)}

lyudmila [28]

Answer:

the answer is 53454

Step-by-step explanation:

1+1=1

6 0

2 years ago

let X represent the amount of time till the next student will arriv ein the library partking lot at the university. If we know t

AlekseyPX

Answer:

0.606531 = 60.6531% probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot.

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

Mean of 4 minutes

This means that $m = 4, \mu = \frac{1}{4} = 0.25$

Find the probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot:

This is:

$P(2 \leq X \leq 132) = P(X \leq 132) - P(X \leq 2)$

In which

$P(X \leq 132) = 1 - e^{-0.25*132} = 1$

$P(X \leq 2) = 1 - e^{-0.25*2} = 0.393469$

$P(2 \leq X \leq 132) = P(X \leq 132) - P(X \leq 2) = 1 - 0.393469 = 0.606531$

0.606531 = 60.6531% probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot.

4 0

2 years ago

Reptile [31]

Answer:

The real zeros of f(x) are x = 0.3 and x = -3.3.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this problem, we have that:

$f(x) = x^{2} + 3x - 1$

$a = 1, b = 3, c = -1$

$\bigtriangleup = 3^{2} - 4*1*(-1) = 13$

$x_{1} = \frac{-3 + \sqrt{13}}{2*1} = 0.3$

$x_{2} = \frac{-3 - \sqrt{13}}{2*1} = -3.3$

The real zeros of f(x) are x = 0.3 and x = -3.3.

7 0

2 years ago

Please help solve the problem below.

ivann1987 [24]

Answer:

1. x = 2

2. x = 5

3. x = 8

4. x = 28

5. x = 13

6. x = 11

7. x = 0

8. x = 72

9. x = 6

10. x = 38

Step-by-step explanation:

hope that helps!

1. subtract 6 on both sides

2. add 3 on both sides

3. divide both sides by 2

4. multiply both sides by 2

5. add 8 on both sides

6. subtract 9 on both sides

7. add 5 on both sides

8. multiply both sides by 6

9. divide both sides by 4

10. add 18 on both sides

3 0

2 years ago