Consider the sets below. U = {x | x is a real number} A = {x | x is an odd integer} R = {x | x = 3, 7, 11, 27} Is R ⊂ A? yes, be

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Consider the sets below. U = {x | x is a real number} A = {x | x is an odd integer} R = {x | x = 3, 7, 11, 27} Is R ⊂ A? yes, be

cause all the elements of set A are in set R yes, because all the elements of set R are in set A no, because each element in set A is not represented in set R no, because each element in set R is not represented in set A

Mathematics

1 answer:

zalisa [80] · Answer 1 · 2023-12-13T15:09:52+03:00

The true statement about R ⊂ A is (a) yes, because all the elements of set A are in set R

<h3>How to determine the set operations?</h3>

The sets are given as:

U = {x | x is a real number}

A = {x | x is an odd integer}

R = {x | x = 3, 7, 11, 27}

From the given sets, we can see that the elements in set R are odd numbers

This means that the set R is a subset of set A

This is represented as:

R ⊂ A

Hence, the true statement about R ⊂ A is (a) yes, because all the elements of set A are in set R