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MariettaO [177]
1 year ago
14

The missing boxes please help

Mathematics
1 answer:
zalisa [80]1 year ago
6 0
Multiply each scale factor by the first set of given perimeter and area
As shown in the picture below

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at a bakery, the ratio of the number of pies to the number of cakes was 8:3. What is the fraction of the number of cakes to the
Ber [7]

Answer:

Step-by-step explanation:

7 0
2 years ago
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Robert earns $8.75 per hour. If he works 15.3 hours each week, how much money will Robert earn in one year? (1 year=52 weeks
Elina [12.6K]
8.75 x 15.3 = 133.875 x 52 = 6961.5
7 0
2 years ago
If you travel 70000 M at a rate of 25 m/s and , how long does it take to complete the trip?
ivolga24 [154]

Answer:

Time=2800 seconds.

Time in minutes= 46.67 minutes

Time in hours= 0.778 hours

Step-by-step explanation:

Distance traveled= 70000 m

Rate or speed of travel= 25m/s

To calculate the time for the travel, we multiply the rate of travel by the distance covered or traveled.

Rate= distance/time

Time= distance/rate

Time= 70000/25

Time=2800 seconds.

Time in minutes= 2800/60

Time in minutes= 46.67 minutes

Time in hours = 2800/(60*60)

Time in hours= 2800/360

Time in hours= 0.778 hours

8 0
3 years ago
Find the value of x..helppp
alekssr [168]

Answer:

For the diagram to be a parallelogram, then the measure of x is 4

Step-by-step explanation:

If the diagram is a parallelogram, then the diagonals bisect each other

What this mean is that they divide each other into 2

Mathematically, this means that the values AC is divided into two equal parts AE and CE

That means;

5x + 28 = 3x + 36

5x-3x = 36-28

2x = 8

x = 8/2

x = 4

8 0
2 years ago
A small plane took 3 hours to fly 960 km from Ottawa to Halifax with a tail wind. On the return trip, flying into the wind, the
Rina8888 [55]

Answer:

  • Wind speed: \rm 40\; km \cdot h^{-1}.
  • Speed of the plane in still air: \rm 320\; km \cdot h^{-1}.

Step-by-step explanation:

This problem involves two unknowns:

  • wind speed, and
  • speed of the plane in still air.

Let the speed of the wind be x \rm \; km \cdot h^{-1}, and the speed of the plane in still air be y\rm \; km \cdot h^{-1}. It takes at least two equations to find the exact solutions to a system of two variables.

Information in this question gives two equations:

  • It takes the plane three hours to travel \rm 960\; km from Ottawa to with a tail wind (that is: at a ground speed of x + y.)
  • It takes the plane four hours to travel \rm 960\; km from Halifax back to Ottawa while flying into the wind (that is: at a ground speed of -x + y.)

Create a two-by-two system out of these two equations:

\left\{ \begin{aligned}&3(x + y) = 960 && (1) \\ &4(-x + y) = 960 && (2) \end{aligned}\right..

There can be many ways to solve this system. The approach below avoids multiplying large numbers as much as possible.

Note that this system is equivalent to

\left\{ \begin{aligned}&4 \times 3 (x + y) = 4\times960 && 4 \times (1) \\ &3\times 4(-x + y) = 3\times 960 && 3 \times (2) \end{aligned}\right..

\left\{ \begin{aligned}&12 x + 12y = 4\times960 && 4 \times (1) \\ &- 12x + 12y = 3\times 960 && 3 \times (2) \end{aligned}\right..

Either adding or subtracting the two equations will eliminate one of the variables. However, subtracting them gives only 1 \times 960 on the right-hand side. In comparison, adding them will give 7 \times 960, which is much more complex to evaluate. Subtracting the second equation (3 \times (2)) from the first (4 \times (1)) will give the equation

(12 - (-12) x = 1 \times 960.

24 x = 960.

x = 40.

Substitute x back into either equation (1) or (2) of the original system. Solve for y to obtain y = 320.

In other words,

  • Wind speed: \rm 40\; km \cdot h^{-1}.
  • Speed of the plane in still air: \rm 320\; km \cdot h^{-1}.
3 0
3 years ago
Read 2 more answers
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