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1 year ago

The missing boxes please help

Mathematics

1 answer:

zalisa [80]1 year ago

6 0

Multiply each scale factor by the first set of given perimeter and area
As shown in the picture below

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<B Round your answer to the nearest hundredth. 2 А 3 ? B

Svet_ta [14]

Answer:

∠ B ≈ 41.81°

Step-by-step explanation:

Using the sine ratio in the right triangle

sin B = $\frac{opposite}{hypotenuse}$ = $\frac{AC}{AB}$ = $\frac{2}{3}$ , thus

B = $sin^{-1}$ ( $\frac{2}{3}$ ) ≈ 41.81° ( to the nearest hundredth )

5 0

3 years ago

I WILL MARK BRAINLIEST

Ber [7]

Answer:

N is (8,5)

Step-by-step explanation:

Find the difference between M, and A, then add it to the M coordinates

The difference between M (x) and A (x) is 3, so you have to add 3 to M's x coordinate to get the N's x coordinate.

Do the same for the y coords and you will get (8,5)

5 0

2 years ago

Why did the SDS build a case against the university?

Readme [11.4K]

This isn’t a math equation

7 0

3 years ago

Mohamed decided to track the number of leaves on the tree in his backyard each year The first year there were 500 leaves Each ye

svetlana [45]

Answer:

The required recursive formula is

$f(n)= 500\times(1.4)^{n-1}\\$

Step-by-step explanation:

Mohamed decided to track the number of leaves on the tree in his backyard each year.

The first year there were 500 leaves

$Year \: 1 = 500$

Each year thereafter the number of leaves was 40% more than the year before so that means

$Year \: 2 = 500(1+0.40) = 500\times 1.4\\$

For the third year the number of leaves increase 40% than the year before so that means

$Year \: 3 = 500\times 1.4(1+0.40) = 500 \times 1.4^{2}\\$

Similarly for fourth year,

$Year \: 4 = 500\times 1.4^{2}(1+0.40) = 500\times 1.4^{3}\\$

So we can clearly see the pattern here

Let f(n) be the number of leaves on the tree in Mohameds back yard in the nth year since he started tracking it then general recursive formula is

$f(n)= 500\times(1.4)^{n-1}\\$

This is the required recursive formula to find the number of leaves for the nth year.

Bonus:

Lets find out the number of leaves in the 10th year,

$f(10)= 500\times(1.4)^{10-1}\\\\f(10)= 500\times(1.4)^{9}\\\\f(10)= 500\times20.66\\\\f(10)= 10330$

So there will be 10330 leaves in the 10th year.

3 0

3 years ago

Read 2 more answers

In one season a basketball team won 60 games and lost 20 games what are the ratios of games won to games lost

Nutka1998 [239]

Answer: 3:1

Step-by-step explanation: For every 3 wins, there is 1 loss. 60/20=3 20/20=1.

7 0

1 year ago

Read 2 more answers