209 is the answer to you problem hope it helps
The <u>different</u> selections of<u> one</u> meat and <u>one</u> vegetable are possible are 18 selections.
Since the Hickory Stick has a selection of 3 meats and 6 vegetables, the number of ways we can select <u>one </u>meat out of 3 is ³C₁ = 3.
Also, the number of ways we can select <u>one </u>vegetable out of 6 is ⁶C₁ = 6.
So, the total number of selections of <u>one</u> meat and <u>one</u> vegetable is ³C₁ × ⁶C₁ = 3 × 6
= 18 selections
So, the <u>different</u> selections of<u> one</u> meat and <u>one</u> vegetable are possible are 18 selections.
Learn more about combination here:
brainly.com/question/19341024
Answer:
5 customers
Step-by-step explanation:
If she takes 1 hour to trim and 1 hour to style, she will take 2 hours per customer.
She plans to work 3 hours a day. So, she can only fit 1 customer in per day because if she scheduled 2 she would need at least 4 hours.
If she can only have 1 customer per day over a 5 day week she will only be able to schedule 5 customers per week.
Looking at the eqaution I believe it's C.
Answer:
1193.2 sq. in.
Step-by-step explanation:
SA = LA + 2B
where LA is the lateral area and B is the area of the base (circle)
B = πr^2 = 3.14(10)^2 = 3.14(100) = 314
Area of 2 Bases = 2 (314) = 628
LA = Ch where C is the circumference of the base
LA = πdh = 3.14(20)(9) = 565.2
SA = 628 + 565.2 = 1193.2 sq. in.
