The total number of matchbooks required would 5,000 be and the cost would be $144
<h3>Mathematical ratios</h3>
50 matchbooks = $1.44
Each matchbook = 0.005 grams red phosphorus
25 grams of red phosphorus is needed:
25/0.005 = 5,000 matchbooks
5,000 matchbooks will cost:
5000/50 x 1.44 = $144
More on mathematical ratios can be found here: brainly.com/question/20387079
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Answer:
The pressure of CO2 = 0.48 atm
Explanation:
Step 1: Data given
Kp = 0.23
Step 2: The balanced equation
2NaHCO3(s) ↔ Na2CO3(s) + CO2(g) + H2O(g)
Step 3: Calculate the pressure of CO2
Kp = (p(CO2))*(p(H2O))
For 1 mol CO2 we have 1 mol H2O
x = p(CO2) = p(H2O)
Kp = 0.23 = x*x
x = √0.23
x = 0.48
pCO2 = x atm = 0.48 atm
The pressure of CO2 = 0.48 atm
Answer:
2Mg + O₂ ⟶ 2MgO
Explanation:
Step 1. Start with the most complicated-looking formula (O₂?).
Put a 1 in front of it.
Mg + 1O₂ ⟶ MgO
Step 2. Balance O.
We have fixed 2 O on the left. We need 2O on the right. Put a 2 in front of MgO.
Mg + 1O₂ ⟶ 2MgO
Step 3. Balance Mg.
We have fixed 2 Mg on the right-hand side. We need 2 Mg atoms on the left. Put a 2 in front of Mg.
2Mg + 1O₂ ⟶ 2MgO
Every formula now has a coefficient. The equation should be balanced. Let’s check.
<u>Atom</u> <u>On the left</u> <u>On the righ</u>t
Mg 2 2
O 2 2
All atoms are balanced.
The balanced equation is
2Mg + O₂ ⟶ 2MgO
