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2 years ago

When an acid is dissolved in water, how does it change the solution's ph?

Chemistry

1 answer:

iren2701 [21]2 years ago

5 0

When an acid is dissolved in water, by releasing protons into the solution, it lowers the pH.

What is pH?

The letters pH stand for the potential of hydrogen since pH is essentially a measurement of the number of hydrogen ions (i.e. protons) in a substance. The pH scale was created in 1923 by scientist Peter Lauritz Srensen. (1868-1969).

The pH of a solution is a key marker of its chemical makeup. The pH can have an impact on the biological processes that take place, the behavior of bacteria, and the behavior of chemicals.

To learn more click the given link.

brainly.com/question/22390063

#SPJ4

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_Li + __F2 → _LIF How do I balance this?

Semmy [17]

Answer:

2Li + F₂ → 2LiF

Explanation:

The reaction expression is given as:

Li + F₂ → LiF

We are to balance the expression. In that case, the number of atoms on both sides of the expression must be the same.

Let use a mathematical approach to solve this problem;

Assign variables a,b and c as the coefficients that will balance the expression:

aLi + bF₂ → cLiF

Conserving Li: a = c

F: 2b = c

let a = 1, c = 1 and b = $\frac{1}{2}$

Multiply through by 2;

a = 2, b = 1 and c = 2

2Li + F₂ → 2LiF

5 0

3 years ago

There are two naturally occurring isotopes of bromine. 79Br has a mass of 78.9183 amu. 81Br has a mass of 80.9163 amu. Determine

Ede4ka [16]

Atomic mass of Br = 79.904
Now lets say y% is abundance of 79Br. 
Then abundance of 81Br = (100 - y) 
mass due to 79Br = 78.9183 * y/100 = 0.789183y
mass due to 81Br = 80.9163 x (100 - y)/100 = 0.809163(100 - y) 
Therfore
0.789183y+ 0.809163(100 - y) = 79.904 
0.789183y + 80.9163 - 0.809163y = 79.904 
 - 0.01998y= 79.904 - 80.9163
= - 1.0123 
y = 1.0123/0.01998 = 50.67% 
 79Br = 50.67% 
now
81Br = 100 - 50.67 = 49.33%
hope this helps

4 0

4 years ago

Why do scientists use scientific notation to represent very small and large numbers?

sergij07 [2.7K]

Answer:

to simplify the number by using fewer digits

Explanation:

6 0

3 years ago

The following reaction shows the products when sulfuric acid and aluminum hydroxide react.

SSSSS [86.1K]

Answer:

There will remain 11.47 grams of Al(OH)3

Explanation:

Step 1: Data given

Mass of sulfuric acid = 35.0 grams

Molar mass sulfuric acid = 98.08 g/mol

Mass of aluminium hydroxide = 30.0 grams

Molar mass of aluminium hydroxide = 78.0 g/mol

Step 2: The balanced equation

2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O

Step 3: Calculate moles

Moles = mass / molar mass

Moles Al(OH)3 = 30.0 grams / 78.0 g/mol

Moles Al(OH)3 = 0.385 moles

Moles H2SO4 = 35.0 grams / 98.08 g/mol

Moles H2SO4 = 0.357 moles

Step 4: Calculate the limiting reactant

For 2 moles Al(OH)3 we need 3 moles H2SO4 to produce 1 mol Al(SO4)3 and 6 moles H20

H2SO4 is the limiting reactant. It will completely be consumed ( 0.357 moles). Al(OH)3 is in excess. There will be react 2/3 * 0.357 = 0.238 moles

There will remain 0.385 - 0.238 = 0.147 moles

Mass of Al(OH)3 remaining = 0.147 moles* 78.0 g/mol = 11.47 grams

There will remain 11.47 grams of Al(OH)3

6 0

3 years ago

How many moles of water can be produced from the reaction of 28g of C3H8

Montano1993 [528]

2.55 moles H20 will be produced

7 0

3 years ago