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MAVERICK [17]
3 years ago
10

Sodium carbonate, Na2CO3(s), can be prepared by heating sodium bicarbonate, NaHCO3(s). 2 NaHCO3(s) Na2CO3(s) + CO2(g) + H2O(g) K

p = 0.23 at a certain temp If a sample of NaHCO3 is placed in an evacuated flask and allowed to achieve equilibrium, what will the pressure of CO2(g) be?
Chemistry
1 answer:
Elenna [48]3 years ago
5 0

Answer:

The pressure of CO2 = 0.48 atm

Explanation:

Step 1: Data given

Kp = 0.23

Step 2: The balanced equation

2NaHCO3(s) ↔ Na2CO3(s) + CO2(g) + H2O(g)

Step 3: Calculate the pressure of CO2

Kp = (p(CO2))*(p(H2O))

For 1 mol CO2 we have 1 mol H2O

x = p(CO2) = p(H2O)

Kp = 0.23 = x*x

x = √0.23

x = 0.48

pCO2 = x atm = 0.48 atm

The pressure of CO2 = 0.48 atm

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A sample of 42 mL of carbon dioxide gas was placed in a piston in order to maintain a constant 101 kPa of pressure.
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The answer to your question is 33.4 ml

Explanation:

Data

volume 1 = V1 = 42 ml

temperature 1 = T1 = 20°C

temperature 2 = T2 = -60°C

Volume 2 = V2 = x

Process

1.- Convert celsius to kelvin

T1 = 20 + 273 = 293°K

T2 = -60 + 273 = 233°K

2.- Use the Charles' law to solve this problem

               \frac{V1}{T1} = \frac{V2}{T2}

Solve for V2

                V2 = \frac{V1T2}{T1}

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               V2 = \frac{(42)(233)}{293}

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