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MAVERICK [17]
3 years ago
10

Sodium carbonate, Na2CO3(s), can be prepared by heating sodium bicarbonate, NaHCO3(s). 2 NaHCO3(s) Na2CO3(s) + CO2(g) + H2O(g) K

p = 0.23 at a certain temp If a sample of NaHCO3 is placed in an evacuated flask and allowed to achieve equilibrium, what will the pressure of CO2(g) be?
Chemistry
1 answer:
Elenna [48]3 years ago
5 0

Answer:

The pressure of CO2 = 0.48 atm

Explanation:

Step 1: Data given

Kp = 0.23

Step 2: The balanced equation

2NaHCO3(s) ↔ Na2CO3(s) + CO2(g) + H2O(g)

Step 3: Calculate the pressure of CO2

Kp = (p(CO2))*(p(H2O))

For 1 mol CO2 we have 1 mol H2O

x = p(CO2) = p(H2O)

Kp = 0.23 = x*x

x = √0.23

x = 0.48

pCO2 = x atm = 0.48 atm

The pressure of CO2 = 0.48 atm

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The most accurately represented John Dalton's model of the atom is: C. a tiny, solid sphere with a predictable mass for a given element

<h3>Further explanation</h3>

The development of atomic theory starts from the first term conveyed by Greek scientists who suggested that every substance has the smallest particles so that the word atomos appears, which means it cannot be divided. So, John Dalton, a British scientist put forward the hypothesis about atoms, among others:

  • 1. The elements are composed of atoms which are small particles which cannot be subdivided
  • 2. Atoms that make up the same element have the same properties, mass, and size, while for different elements, the properties are also different
  • 3. Compounds are composed of two or more atoms in a fixed ratio
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Point 3 shows the relationship with The Law of Constant Composition of Proust so that further research on atoms is more developed

Dalton's hypothesis is described as a solid sphere like a very small shot put ball or a bowling ball based on Dalton's hobby in bowling

<h3>Learn more</h3>

Bohr's model of the atom

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Keywords: atom, Dalton, a solid sphere, The Law of Constant Composition

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What refers to the attractive forces that exist between molecules?​
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8 0
3 years ago
I need help solving this!
zmey [24]

Answer: Moles of hydrogen required are 4.57 moles to make 146.6 grams of methane, CH_{4}.

Explanation:

Given: Mass of methane = 146.6 g

As moles is the mass of a substance divided by its molar mass. So, moles of methane (molar mass = 16.04 g/mol) are calculated as follows.

Moles = \frac{mass}{molar mass}\\= \frac{146.6 g}{16.04 g/mol}\\= 9.14 mol

The given reaction equation is as follows.

C + 2H_{2} \rightarrow CH_{4}

This shows that 2 moles of hydrogen gives 1 mole of methane. Hence, moles of hydrogen required to form 9.14 moles of methane is as follows.

Moles of H_{2} = \frac{9.14}{2}\\= 4.57 mol

Thus, we can conclude that moles of hydrogen required are 4.57 moles to make 146.6 grams of methane, CH_{4}.

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Answer:

V = 85.2

Explanation:

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Considering what we know about STP, we get the moles, temperature, and pressure. Using the ideal gas law we can find the volume (PV = nRT). Plug in our variables: (1 * V = 3.80 * R * 273). Since we are dealing with atm and not kPA or mmHg, we use the constant for atm (0.0821) which we use for R. (So.. now our equation is 1 * V = 3.80 * 0.0821 * 273). We now multiply the right side to get 85.17054. So... V = 85.2 considering sigificant figures (this is the part where I am the least sure of, since I havent done sig figs in a while)

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