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Rina8888 [55]
3 years ago
9

suppose you make lemonade with one can lemonade concentrate mixed with four cans of water. What is the fraction of the final pro

duct that is water
Chemistry
1 answer:
Airida [17]3 years ago
4 0

Answer:

0.8 part of the product is water

Explanation:

Volume (or parts) of water = 4

Volume (or parts) of lemonade = 1

Total volume = 4 + 1 = 5

Fraction of water = Volume of water / Total volume = 4 / 5 = 0.8

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Is filling up beakers with 200ml of water bad
iogann1982 [59]

Answer:

No

Explanation:

Filling a beaker 200ml of water is not bad because Each beaker's capacity may vary according to the size of different beaker.

6 0
4 years ago
Describe how you mathematically convert the measured mass of a
RoseWind [281]

Answer:

no. of moles = measured mass of substance/ molar mass of the constituted elements

Explanation:

No. of moles of 2.0g NaCl= 2/(23+35.5) = 0.034mol

3 0
3 years ago
How do you calculate the Atomic Mass of an element?
Leno4ka [110]

Answer:

with the help of adding mass of protons and neutrons

Explanation:

measuring the atomic mass of an element , we add up the proton mass with the neutron mass it gives us the atomic mass

5 0
4 years ago
How does the entropy of a system change when equal volumes of ethanol and water are mixed to form a solution? these are the answ
shutvik [7]
When equal volumes of ethanol and water are mixed to form a solution, the entropy of the resulting solution increases. This is because ethanol and water are both polar substances, making them miscible. The solubility of both substances is high because they have similar attractions due to the presence of hydrogen bonding. This means that molecules of water and ethanol freely move with each other, therefore increasing the dispersal, randomness, and disorder (entropy) of the system.
5 0
3 years ago
The 1995 Nobel Prize in chemistry was shared by Paul Crutzen, F. Sherwood Rowland, and Mario Molina for their work concerning th
Nikolay [14]

Answer:

\Delta H_{rxn3}=-162.5 kJ/mol

Explanation:

The reaction we need to calculate:

O_3 (g) + Cl (g) \longrightarrow ClO (g) + O_2 (g)

1) O_3 (g) + ClO (g) \longrightarrow Cl (g) +2 O_2 (g)

\Delta H_{rxn}=-122.8 kJ/mol

We need the ClO in the products side, so we use the inverse of this reaction:

Cl (g) +2 O_2 (g) \longrightarrow O_3 (g) + ClO (g)

\Delta H_{rxn1}=122.8 kJ/mol

2) 2 O_3 (g) \longrightarrow 3 O_2 (g)

\Delta H_{rxn2}=-285.3 kJ/mol

Now we need to combine this two:

Cl (g) +2 O_2 (g) + 2 O_3 (g)\longrightarrow O_3 (g) + ClO (g) + 3 O_2 (g)

Cl (g) + O_3 (g)\longrightarrow ClO (g) + O_2 (g)

The enthalpy of reaction:

\Delta H_{rxn3}=\Delta H_{rxn1}+ \Delta H_{rxn2}=122.8 kJ/mol-285.3 kJ/mol

\Delta H_{rxn3}=-162.5 kJ/mol

4 0
3 years ago
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