N2 (g) + O2 (g) = 2NO (g)
Decreasing the volume would cause the equilibrium to shift to the side with less moles on it. Because both sides have the same number of moles (2) there would be no change to the equilibrium.
Hope I helped!
Answer:
852g
Explanation:
From the question given, we obtained the following information:
Molarity = 3M
Volume = 2L
Mole =?
First, we need to find the number of mole of Na2SO4 present in 2L of the solution. This is achieved by doing the following:
Molarity = mole /Volume
Mole = Molarity x Volume
Mole = 3 x 2 = 6moles
Next, we'll find the molar mass of Na2SO4, as illustrated below:
Molar Mass of Na2SO4 = (23x2)+32+(16x4) = 46 + 32 + 64 = 142g/mol
Recall:
Number of mole = Mass /Molar Mass
Mass = number of mole x molar Mass
Mass = 6 x 142 = 852g
Avogadro's number is 1 mol = 6.02 * 10^23 elements
It means that 1 mol of atoms is 6.02 * 10^23 atoms
1 mol of atoms = 6.02 * 10^23 atoms
From there, if you divide both sides by 1 mol of atoms, you get
1 = 6.02 * 10^23 atoms / 1 mol of atoms.
That means, that to pass from a number of moles of atoms to number of atoms you have to multipby by the conversion factor
6.02*10^23 atoms Al/ 1 mol Al
That is the second option of the list.
It's a combination of carbon dioxide gas from the dry ice, and tiny water droplets.) ... The dry ice fog is heavier (denser) than air, so it sinks down. But it's less dense than water, so it floats on the water. The bubbles are heavier than air, but less dense than carbon dioxide fog, so they'll float on the fog.