Question

3x+4y^2=7z (solve for y)

Answer 1

Answer:

$y = + - \sqrt{ \frac{7}{4} } z - \frac{3}{4} x$

Step-by-step explanation:

$3x + 4y^{2} = 7z$

$4y^{2} = 7z - 3x$

Divide both sides by 4

${y}^{2} = \frac{7}{4} z - \frac{3}{4} x$

$\sqrt{ {y}^{2} } = \sqrt{ \frac{7}{4} } z - \frac{3}{4} x$

Final answer:

$y = + - \sqrt{ \frac{7}{4} } z - \frac{3}{4} x$