The 100th term of 70, 100, 130

Mathematics

1 answer:

fgiga [73]2 years ago

6 0

Answer:

3040

Step-by-step explanation:

given arithmetic progression is

70,100,130,...

here

first term (a)=70

common difference (d)=100-70=30

number of term n=100

using the formula of arithmetic progression

an=a+(n-1)d

a100=70+(100-1)30

a100=70+99×30

a100=70+2970

a100=3040

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