The probability that the transistor will last between 12 and 24 weeks is 0.424
X= lifetime of the transistor in weeks E(X)= 24 weeks
O,= 12 weeks
The anticipated value, variance, and distribution of the random variable X were all provided to us. Finding the parameters alpha and beta is necessary before we can discover the solutions to the difficulties.
X~gamma(
)
E(X)=
=
=6 weeks
V(x)=
=24/6= 4
Now we can find the solutions:
The excel formula used to create Figure one is as follows:
=gammadist(X,
,
, False)
P(
)
P(
)
P(
)
P= 0.424
Therefore, probability that the transistor will last between 12 and 24 weeks is 0.424
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Answer:
second option
Step-by-step explanation:
Given the rule
(x, y ) → (x + 3, y - 5)
This means add 3 to the original x- coordinate and subtract 5 from the original y- coordinate, that is
D(4, - 4 ) → D'(4 + 3, - 4 - 5 ) → D'(7, - 9 )
E(5, - 5 ) → E'(5 + 3, - 5 - 5 ) → E'(8, - 10 )
9514 1404 393
Answer:
a = 9 meters
Step-by-step explanation:
The perimeter is the sum of the side lengths:
28 m = a + 2m + a + 8m
18 m = 2a . . . . . . . . . . . . . . . . subtract 10m, collect terms
9 m = a . . . . . . . . . . . . . . . divide by 2
The value of a is 9 meters.