Answer:
2/3, 4/6, -4/-6... gtg sorry if you needed more
Step-by-step explanation:
You can use substitution for this.
x+5 = 5x -11
Combine like terms
16=4x
Divide 4 on both sides to isolate the x
x=4
Plug x=4 to one of the equations
y= 4 +5
Combine like terms
y=9
So the answer is A. (4,9)
I hope this helps you out a bunch hun :)
So what we do is
area that remains=total area-triangle area that was cut out
we need to find 2 things
total area
triangle area
total area=rectange=base times height
area=(3x+4) times (2x+3)
FOIL or distribute
6x^2+8x+9x+12=6x^2+17x+12
triangle area=1/2 times base times height
triangle area=1/2 times (2x+2) times (x-2)=
(x+2) times (x-2)=x^2+2x-2x-4=x^2-4
so
total area=6x^2+17x+12
triangle area=x^2-4
subtract
area that remains=total area-triangle area that was cut out
area that remains=6x^2+17x+12-(x^2-4)=
6x^2+17x+12-x^2+4=
6x^2-x^2+17x+12+4=
5x^2+17x+16
area that remains is 5x^2+17x+16
