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ICE Princess25 [194]
3 years ago
6

Jeremy is hosting a Halloween party for 80 children.He will give each child at least one candy bar.If each bag of candy contains

18 candy bars,which inequality can be used to determine how many bags ,c,Jeremy will need to buy
Mathematics
2 answers:
Firdavs [7]3 years ago
3 0
Jeremy needs 20 bags of candy to buy for his party to give to 80 kids at a halloween party

kupik [55]3 years ago
3 0
5= 90 so she will have 10 candy bars left . I think !
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L= Q_1 - 1.5*IQR = 210 -1.5*40 =150

U= Q_3 + 1.5*IQR = 250 +1.5*40 =310

And if we analyze the info provided we have 500 values

Tails: 160,165,167,171,175,...,268,269,269,269,270,270

So as we can see on the tails any values is <150 or >310 so then for this case we cannot consider as outliers any of the values on the tails of the distribution.

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For this case we have the 5 number summary

(160,210,220,250,270)

So then we have:

minimum = 160 , Q1 = 210, Q2= Median=220, Q3 = 250, Max=270

If we find the interquartile range we got:

IQR = Q_3 -Q_1 = 250-210 =40

For this case we need to find the lower and upper limit with the following formulas:

L= Q_1 - 1.5*IQR = 210 -1.5*40 =150

U= Q_3 + 1.5*IQR = 250 +1.5*40 =310

And if we analyze the info provided we have 500 values

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