All categories

2 years ago

HELP ME ASAP!!!

Mathematics

1 answer:

Olenka [21]2 years ago

8 0

Answer:

21.6 liters

Step-by-step explanation:

40 drops make up a volume of 10 mL

Therefore, the volume of 1 drop of water = 10mL/40 = 1/4 mL= 0.25mL

Since the tap loses 1 drop of water in 1 sec, it loses 0.25mL of water in 1 second

60 seconds make up 1 second so volume of water lost in 1 minute = 0.25 x 60 = 15 mL

60 minutes make up 1 hour so volume of water lost in 1 hour = 15 x 60 = 900 mL

24 hours make up a day so volume of water lost in 1 day = 900 x 24 = 21,600 mL

Since 1000 mL make up 1 liter, divide by 1000 to get volume in liters

Volume of water lost in 1 day = 21600/1000 = 21.6 liters

Can be done as one equation

V lost in one day = 0.25 x 3600 x 24 mL = 21600 mL = 21.6 L

You might be interested in

What is −4 4/5÷4 in lowest terms??

gregori [183]

-4 4/5 ÷ 4 = -24/5 x 1/4 = -6/5 = -1 1/5

8 0

3 years ago

Identify each coefficient <br> 1. 8x___

masha68 [24]

8 would be the coefficient :)

5 0

3 years ago

Which could be the dimensions of a rectangular prism whose surface area is less than 160 square feet? Select two options

Hunter-Best [27]

Answer:

8 4 3 and 7 6 4 my chat is devanson1

5 0

3 years ago

A hoop, a uniform solid cylinder, a spherical shell, and a uniform solid sphere are released from rest at the top of an incline.

Serjik [45]

Answer:

Step-by-step explanation:

Given

Hoop, Uniform Solid Cylinder, Spherical shell and a uniform Solid sphere released from Rest from same height

Suppose they have same mass and radius

time Period is given by

$t=\sqrt{\frac{2h}{a}}$ ,where h=height of release

a=acceleration

$a=\frac{g\sin \theta }{1+\frac{I}{mr^2}}$

Where I=moment of inertia

a for hoop

$a=\frac{g\sin \theta }{1+\frac{mr^2}{mr^2}}$

$a=\frac{g\sin \theta }{2}$

a for Uniform solid cylinder

$a=\frac{g\sin \theta }{1+\frac{mr^2}{2mr^2}}$

$a=\frac{2g\sin \theta }{3}$

a for spherical shell

$a=\frac{g\sin \theta }{1+\frac{2mr^2}{3mr^2}}$

$a=\frac{3g\sin \theta }{5}$

a for Uniform Solid

$a=\frac{g\sin \theta }{1+\frac{2mr^2}{5mr^2}}$

$a=\frac{5g\sin \theta }{7}$

time taken will be inversely proportional to the square root of acceleration

$t_1=k\sqrt{2}=1.414k$

$t_2=k\sqrt{\frac{3}{2}}=1.224k$

$t_3=k\sqrt{\frac{5}{3}}=1.2909k$

$t_4=k\sqrt{\frac{7}{5}}=1.183k$

thus first one to reach is Solid Sphere

second is Uniform solid cylinder

third is Spherical Shell

Fourth is hoop

3 0

3 years ago

Is 3/4 greater than 7/8?

yKpoI14uk [10]

3/4 = (2*3) / (2* 4) = 6/8

7/8.

Is 3/4 greater than 7/8?
Is like asking is 6/8 greater than 7/8? Because 3/4 is equivalent to 6/8.

The answer is No.

3 0

3 years ago

Read 2 more answers