Answer:
a) at x=0.5 y=2 and at x=1 y=2 this similarity in values shows that the solution for x is between 0.5 and 1
c) The x solution will be between x=0.0 and x=0.7 .
There is a similarity in values of y at x=0.6, y=2.4 and at x=0.7 , y=2.4
d) For x= (0.6+0.7)/2 = 1.3/2 =0.65
For y= (2.4+2.3)/2 =4.7/2=2.35
Approximate solution is (0.65, 2.35)
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Answer:
a = 9/2
Step-by-step explanation:
In order for the equation to be true, the value of the scalar multiplier must be ...
15/3 = -10/-2 = 35/7 = 5
So, you're solving ...
(2/3)a + 2 = 5
(2/3)a = 3 . . . . . . subtract 2
a = 9/2 . . . . . . . . multiply by 3/2
Note:
If fx(x) changes from f(x₁) to f(x₂), the rate of change is
Rate = [f(x₂) - f(x₁)]/(x₂ - x₁)
From the table, we can compute rates of change as follows:
Change in x Change in f(x) Change in x Rate
----------------- -------------------- ----------------- ---------
[-4,-2] 0 - (-12) = 12 0 - (-2) = 2 6
[-2, 1] 3 - 0 = 3 1 - (-2) = 3 1
[-3, 1] 3 - (-5) = 8 1 - (-3) = 4 2
[-4, 0] 4 - (-12) = 16 0 - (-4) = 4 4