"1 indicating a coupon and all other outcomes indicating no coupon"
Probability is (number of successful outcomes) / (number of possible outcomes)
Theoretical Probability of rolling a 1: 1/8
Experimental Probability of using coupons: 4/48 = 1/12
So, the experimental probability of a customer using a coupon (that is, 1/12) is smaller than the theoretical probability of rolling a 1 (that is, 1/8).
Answer:
77/15 = 5.133
Step-by-step explanation:
3 and 2/3 = 11/3
1 and 2/5 = 7/5

The answer is c, 8/3 (6) - 16 = 0 therefore 6 is the zero
Answer:

Step-by-step explanation:
Coordinate of B = 1
Coordinate of D = 6
Coordinate of A = -1
BD = |1 - 6| = 5 units
AD = |-1 - 6| = |-7| = 7 units

Plug in the values
