9514 1404 393
Answer:
Part A: 2 f2
Part B: draw a diagonal (AC, for example); 1 f12
Step-by-step explanation:
Part A:
The area of a parallelogram is given by the
formula
A=bh
where "b' is the length of the base, and 'h' is the
perpendicular distance between the bases.
Using the numbers shown on the diagram, the
area is
A = (3 ft)(2/3 ft) = 3-2/3 f12
A =2 ft2..... area of the parallelogram
Part B:
Typically, a polygon is partitioned into triangles
by drawing diagonals from one of the vertices. It
does not matter which one. (In a quadrilateral,
only one diagonal can be drawn from any given
vertex.) Here, the "base" of each triangle is the
same as the base of the parallelogram: 3 feet.
The "height" of each triangle is the same as the
height of the parallelogram: 2/3 ft.
The area of a triangle is given by the formula
Answer:
no guaranteed classification
Step-by-step explanation:
Both a rectangle and a parallelogram have two pairs of congruent sides. Because we don't know anything about the angles between these sides, it is not possible to establish which kind of figure is.
15x3$=45$
28x4$=112$
But you only had 79$
So the answer is zero
Answer:
The six trig ratios at 3pi/2 are:
sin(3pi/2)=-1
cos(3pi/2)=0
tan(3pi/2) (undefined)
csc(3pi/2)=-1
sec(3pi/2) (undefined)
cot(3pi/2)=0
Step-by-step explanation:
If tangent is undefined then cosine would have to be 0 given that tangent is the ratio of sine to cosine.
cosine is 0 at pi/2 and 3pi/2 in the first rotation of the unit circle.
3pi/2 satisfies the given constraint.
The six trig ratios are therefore:
sin(3pi/2)=-1
cos(3pi/2)=0
tan(3pi/2)=-1/0 (undefined)
Reciprocal values:
csc(3pi/2)=-1
sec(3pi/2) undefined since cos(3pi/2)=0
cot(3pi/2)=0/-1=0
