Can you please help me out i am stuck

Mathematics

2 answers:

My name is Ann [436]3 years ago

6 0

What's the question? what's the question?

Katarina [22]3 years ago

3 0

Hay buddy, yeah sure. I can help but you have to give me the question please. Thank you,I understand that you are stuck a but, but if you could give a litte more information being specific then maby the team at Brainly can help.

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3 years ago

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Equation with angles can someone please answer helpppp

Elden [556K]

Answer:

$x = 18°\\\angle A = 73°$

Step-by-step explanation:

By interior angle property on one side of the transversal.

$\angle A+ \angle B = 180°\\6x - 35° + 3x + 53° = 180°\\9x + 18° = 180°\\9x = 180° - 18°\\9x = 162°\\x = \frac{162°}{9}\\ \huge \red {\boxed {x = 18°}} \\\therefore \angle A = 6x - 35°\\\therefore \angle A = 6\times 18°- 35°\\\therefore \angle A = 108°- 35°\\ \huge \purple {\boxed{\therefore \angle A = 73°}} \\$

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3 years ago

Solve 3x² + 4x = 2. (2 points)

uysha [10]

Answer:

Step-by-step explanation:

As it is a second order equation, it means that it has two possible answers and they are $x_1$ and $x_2$ .

The famous quadratic formula for solving any second order equation is the following:

$x_{1} = \frac{-b + \sqrt{b^2 - 4 ac}}{2a}\\x_{2}=\frac{-b - \sqrt{b^2 - 4 ac}}{2a}$

Where a is the coefficient of $x^2$ , b is the coefficient of x, and c is the free term. In other words,

$a = 3\\b=4\\c=-2$

as the equation should be in the following form:

$a x^2 + bx+c = 0$

Therefore the possible answer should be the following,

$\frac{-4 + \sqrt{4^2 - 4*3*(-2)}}{2*3}=\frac{-4 +\sqrt{16 + 24}}{6} =\frac{-4 + \sqrt{40}}{6}=\\ \frac{-4 + \sqrt{4*10}}{6} = \frac{-4 + 2\sqrt{10}}{6}$ $\frac{2*(-2 + \sqrt{10})}{2*3} = \frac{-2 + \sqrt{10}}{3}$