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Citrus2011 [14]
2 years ago
5

Content area a leased asset will appear on the balance sheet as a long-term asset. true false'

Computers and Technology
1 answer:
Evgen [1.6K]2 years ago
8 0

The given statement is false. The liability for a leased asset should be shown separately in the balance sheet as a current liability or a long-term liability as the case may be.

<h3>What is leased asset?</h3>

A Leased Asset exists as an asset leased by the owner to another party in return for money or any other favor. While leasing an asset, the owner penetrates into a contract permitting the other party the temporary use of an asset.

Long-term assets exist as investments in a company that will benefit the company for many years. Long-term assets can contain fixed assets such as a company's property, plant, and equipment, but can also contain intangible assets, which can't be physically touched such as long-term investments or a company's trademark.

Hence, The given statement is false. A leased asset will appear on the balance sheet as a long-term asset. Revising depreciation estimates involves the amounts of depreciation expenses recorded in past periods. Land acquired as speculation exists reported under Investments on the balance sheet. The liability for a leased asset should be shown separately in the balance sheet as a current liability or a long-term liability as the case may be.

To learn more about leased asset refer to:

brainly.com/question/17214724

#SPJ4

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The computer is restarted. The Recycle Bin or Trash is emptied

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A telecom company wants to extend their horizontal cables over a distance of 510 meters. Which cable should they use?
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A testing lab wishes to test two experimental brans of outdoor pain long each wiil last befor fading . The testing lab makes six
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Answer:

The answer is "\bold{Brand \ A \ (35, 350, 18.7) \ \ Brand \ B \ (35, 50, 7.07)}"

Explanation:

Calculating the mean for brand A:

\to \bar{X_{A}}=\frac{10+60+50+30+40+20}{6}  =\frac{210}{6}=35

Calculating the Variance for brand A:

\sigma_{A}^{2}=\frac{\left ( 10-35 \right )^{2}+\left ( 60-35 \right )^{2}+\left ( 50-35 \right )^{2}+\left ( 30-35 \right )^{2}+\left ( 40-35 \right )^{2}+\left ( 20-35 \right )^{2}}{5} \\\\

     =\frac{\left ( -25 \right )^{2}+\left ( 25  \right )^{2}+\left ( 15\right )^{2}+\left ( -5 \right )^{2}+\left ( 5 \right )^{2}+\left ( 15 \right )^{2}}{5} \\\\ =\frac{625+ 625+225+25+25+225}{5} \\\\ =\frac{1750}{50}\\\\=350

Calculating the Standard deviation:

\sigma _{A}=\sqrt{\sigma _{A}^{2}}=18.7

Calculating the Mean for brand B:

\bar{X_{B}}=\frac{35+45+30+35+40+25}{6}=\frac{210}{6}=35

Calculating the Variance for brand B:

\sigma_{B} ^{2}=\frac{\left ( 35-35 \right )^{2}+\left ( 45-35 \right )^{2}+\left ( 30-35 \right )^{2}+\left ( 35-35 \right )^{2}+\left ( 40-35 \right )^{2}+\left ( 25-35 \right )^{2}}{5}

    =\frac{\left ( 0 \right )^{2}+\left ( 10 \right )^{2}+\left ( -5 \right )^{2}+\left (0 \right )^{2}+\left ( 5 \right )^{2}+\left ( -10 \right )^{2}}{5}\\\\=\frac{0+100+25+0+25+100}{5}\\\\=\frac{100+25+25+100}{5}\\\\=\frac{250}{5}\\\\=50

 Calculating the Standard deviation:  

\sigma _{B}=\sqrt{\sigma _{B}^{2}}=7.07

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